Dear Friends, SBI Clerk 2018 Notification has been released we hope you all have started your preparation. Here we have started New Series of Practice Materials specially for SBI Clerk 2018. Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.
[WpProQuiz 1197]
Click “Start Quiz” to attend these Questions and view Explanation
Direction (Q. 1-5): What will come in the place of question mark (?) in the following number series?
Directions(Q. 6 – 10) : What approximate value will come in place of question mark(?) in the given questions ? (Note : you are not expected to calculate the exact value.)
7).√(624) × 14.02 + √(404) × 15.97 = ?
8).8461 ÷ 11.99 – 24.01 ÷ (5 / 100) = ?
9). (14.85% of 679) + (19.9% of 219.83) = ?
10). 1441÷? + 149.98 × 14.99 = 3006 – 254.91
Direction (Q. 16-20): Study the following graphs carefully and answer the questions that follow:
Answers:
Direction (Q. 1-5):
4, 17, 62, ?, 1894, 13267
4 × 3 + 5 = 17
17 × 4 – 6 = 62
62 × 5 + 7 =317
317 × 6 – 8 = 1894
1894 × 7 + 9 = 13267
Hence, 317 will come in the place of question mark.
6, 8, ?, 22, 36, 58
6 + 8 = 14
8 + 14 = 22
14 + 22 = 36
22 + 36 = 58
Hence, 14 will come in the place of question mark.
0.25, 1, 2.25 , ?, 6.25, 9, 12.25
0.5^2= 0.25
1^2 = 1
1.5^2 = 2.25
2^2 = 4
2.5^2 =6.25
3^2 = 9
3.5^2 = 12.25
Hence, 4 will come in the place of question mark.
(Or)
The difference of difference is 0.5
56, 67, 100 , ?, 232, 331
56 + 11 = 67
67 + 33 = 100
100 + 55 = 155
155 + 77 = 232
232 + 99 = 331
Hence, 155 will come in the place of question mark.
63, 352, 608 , ?, 1029, 1198
63 + 289 = 352
352 + 256 = 608
608 + 225 = 833
833 + 196 = 1029
1029 + 169 = 1198
Hence, 833 will come in the place of question mark.
Directions(Q. 6 – 10) :
6399 × (13 / 8) + 353 ÷ ? = 10444
Or, 6400 ×(13 / 8) + (353 / ?) ≈ 10444
Or, 800 × 13 + (353 / ?) ≈ 10444
Or, (353 / ?) = 10444 – 10400 ≈ 44
Or, ? = 353 / 44 = 8.022 ≈ 8
? = √625 ×14 + √400 × 16
≈ 25 × 14 + 20 × 16 = 350 + 320 = 670
8.Answer is: e
? = 8460 ÷ 12 – 24 × (100 / 5)
= 705 – 24 × 20 = 705 – 480 = 225
? = [(15 × 680) / 100] + [(20 × 220) / 100]
= 102 + 44 ≈ 146 ≈ 145
10).Answer is: a
1441 ÷ ? + 149.98 × 14.99
= 3006 – 254.91
Or, 1441 / ? = 2751 – 150 × 15
= 2750 – 2250 = 500
?= 1440 / 500 = 2.88 = 3
Let’s assume that the required time = T years
Hence in 2nd case, (6336 – 4800) = (4800’8’T)/100
=> T = (1536’100)/(4800’8)
=> T = 4 years
Let’s suppose that the principal amount be Rs P in 1St case.
Hence, P + (P'((5’4)/100)) = 7200
=> 1.2P = 7200
=> P = Rs 6000
Let speeds of Kranthi, Shakthi and Bhakthi be denoted by k, s and b respectively.
It is given that Kranthi beats Shakthi by 10m, this means that while Kranthi has travelled 100m, Shakthi has travelled only (100-10) = 90m or 90%.
=> s X t’=0.9 X k X t’
=> s=0.9 X k …(1)
It is also given that Shakthi beats Bhakthi by 5 secs, this means that:
=> s X t=b X (t+5)=100 …(2)
Also, it is given that: k=2b ..(3)
Using (3) in (1), we get
=> s=0.9 X 2b=1.8b ..(4)
Using (4) in (2), we get
=> 1.8bt=bt+5b =>0.8bt=5b
=> t = 5b/0.8b = 6.25s.
Using this result in (2), we get s = 100/t = 100/6.25 = 16 m/s
Using this result in (1), we get k = sl(0.9) = 16/(0.9) = 17.78 m/s
The favourable cases {(1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 3), (2, 4), (2, 5), (2, 6), (3, 4), (3, 5), (3, 6), (4, 5), (4, 6), (5, 6) }.
Total number of cases = 36
Required probability = 15/36 = 5/12.
Let Shashi and Tinu’s current ages be ‘x’ and ‘y’ years respectively.
Ages z years ago: ‘x – z’ and ‘y – z’
x – z = (1/7) (y – z)
=>7x-7z=y – z
=> 7x – y = 6z —-(i)
Ages in z years from now: ‘x + z’ and ‘y + z’
3(x + z) = y + z
=> 3x + 3z = y + z
=> y – 3x = 2z
=> 3y – 9x = 6z …(ii)
Equating (ii) and (i):
=> 7x – y = 3y – 9x
=> 16x = 4y
=> y/x = 4/1
Let the cost price of one horse and one cow be Rs H and Rs C respectively.
According to the question; 2H + 3C = 72000… (1)
According to the question; 2(1.15H) + 3(0.95C) = 80000
=> 2.3H + 2.85C = 80000… (2)
(2) – (1) gives 0.311- 0.15C = 8000
=> H – 0.5C = 80000/3 … (3)
Solving (1) and (3), we get H = 29000 and C = 4667
H + C = 33667
Direction (Q. 16-20):
(36.2 + 58.8 + 52.6 + 54.4)*1000/4
= 202000/4
= 50500
= (60 × 62% + 40 × 78%)/(63 × 75% + 60.4 × 73%) × 100
= (3720 + 3120)/(4725 + 4409) × 100
= 6840 / 9134 × 100
= 74.88%
= 75%
= (50 × 25% + 58.8 × 22%+ 54.4 × 22%)*1000/3
= (12500 + 12936 + 11968)/3
= 37404/3
= 12468
(40 × 22% + 63 × 25 %) : (36.2 × 38% + 58.8 × 22%)
= 24550 : 26692
= (52.6 × 40% + 54.4 × 22%)/(50 × 25% + 36.2 × 38%) × 100
= (2104 + 1196.8)/ (1250 + 1375.6) × 100
= 3300/2625 × 100
= 125.71
= 125%
Required answer = 125 – 100
= 25% more
This post was last modified on September 17, 2020 10:53 am