Dear Friends, SBI Clerk 2018 Notification has been released we hope you all have started your preparation. Here we have started New Series of Practice Materials specially for SBI Clerk 2018. Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.
Topic | Daily Publishing Time |
Daily News Papers & Editorials | 8.00 AM |
Current Affairs Quiz | 9.00 AM |
Logical Reasoning | 10.00 AM |
Quantitative Aptitude “20-20” | 11.00 AM |
Vocabulary (Based on The Hindu) | 12.00 PM |
Static GK Quiz | 1.00 PM |
English Language “20-20” | 2.00 PM |
Banking Awareness Quiz | 3.00 PM |
Reasoning Puzzles & Seating | 4.00 PM |
Daily Current Affairs Updates | 5.00 PM |
Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
Reasoning Ability “20-20” | 7.00 PM |
English Language (New Pattern Questions) | 8.00 PM |
General / Financial Awareness Quiz | 9.00 PM |
Click “Start Quiz” to attend these Questions and view Explanation
Directions (Q. 1-5): what approximate value will come in place of question mark(?) in the given questions.
1). (36.01)3 × (4096)1/2 × (37.99)2 ÷ (93 × 75.982) = 4?
2). (4809.01 + 9615.96 + 14425.03) ÷ 4.98+6.02 = (?)2
3). (35% of 74000) ÷ ? = (123 % of 13.02)2 × 2.01
4). 4/15 of 393 + 7/12 of 473 = ? × (1.99 + 1.01)
5). √(2809.001) ÷ 7.98 × (12.01)2+ 46.002 = ?
Directions (Q. 6-10): What should come in place of question mark (?) in the following number series:
6). 17, 9, 15, 40, 143.5, ?
7). 3, 5, 13, 49, 241, ?
8). 508, 256, 130, 67, 35.5, ?
9). 7, 13, 31, 85, 247, ?
10). 64, 36, 22, 15, ?, 9.75
Directions (Q. 11-15): Study the following pie-chart and bar graph carefully and answer the questions given below.
Percentage distribution of the number of mobiles sold by a shop during six months
Total number of mobiles sold = 75000
The ratio of the number of mobiles of Redmi to the number of mobiles of Vivo sold during six months
Answers:
Directions (Q. 1-5):
1). Answer c
(36.01)3 × (4096)1/2 × (37.99)2 ÷ (93 × 75.982) = 4?
Or, 4? = [ 363 x √4096 x 382] / 93 × 762
or, (43 x 93 x 43 x 38 x 38) / (93 x 76 × 76)
= (43×43) / (2×2)
Or, 4? = 43 × 42 = 45
? = 5
2). Answer d
(4809.01 + 9615.96 + 14425.03) ÷ 4.98 + 6.02 = (?)2
Or, (?)^2 = [(4809 + 9616 + 14425) / 5] +6
= (28850/5) + 6 = 5770 + 6
Or, ?2 = 5776
? = √5776 = 76
3). Answer b
(35% of 74000) ÷ ? = (123% of 13.02)2 x 2.01
Or, (35×74000)/ 100 ÷ ? = [(123×13) / 100]2 x 2
or, 25900 / ? = (15.99)2 × 2
or, (25900/?) = 16×16×2
?= 25900 / (16×16×2) = 50.58 = 50
4). Answer a
4/15 of 393 + 7/12 of 473
= ? x (1.99 + 1.01)
or, ? x 3 = (4/15) x 393 + (7/12) x 480
or, ? x 3 = (4/15) x390 + (7/12) x 480
or, ? x 3 = 104 + 280
or, ? = 384/3 = 128 = 127
5). Answer c
√2809.001 ÷ 7.98 x (12.01)2+ 46.002 = ?
or, ? = √2809 ÷ 8 x (12)2 + 46
or, ? = (53/8) x (12)2 + 46
or, ? = 954 + 46
? = 1000
Directions (Q. 6-10):
6). Answer c
The series is ×0.5 + 0.5, ×1.5 + 1.5, ×2.5 + 2.5, ×3.5 + 3.5, ×4.5 + 4.5
7). Answer d
The series is ×2-1, ×3-2, ×4-3, ×5-4, ×6-5
8). Answer b
The whole series is /2 + 2
9). Answer c
The series is +3 × 2, +3 × 6, +3 × 18, +3 × 54, +3 × 162
10). Answer c
The whole series is ×0.5 + 4
Directions (Q. 11-15):
Number of mobiles sold by Vivo in the month of November
= 75000 × 15/100 × 6/25 = 2700
37% of mobiles sold by Vivo at a discount
= 2700 × 37/100
= 999
Number of mobiles sold without discount = 2700 – 999
= 1701
Total number of mobiles of Vivo sold during the month of November and December together
= 75000 × 15/100 × 6/25 + 75000 × 11/100 × 11/15
= 2700 + 6050
= 8750
Total number of mobiles Redmi sold during the month of July
= 75000 × 21/25 × 13/100
= 750 × 21/25 × 13
= 8190
Total number of mobiles of Redmi sold during the month of November
= 75000 × 19/25 × 15/100
= 750 × 19/25 × 15
= 8550
Required % = 8190/8550 × 100
= 95.78
= 96%
Required ratio
= 750 × 13 × 4/25 : 750 × 22 × 8/25
= 13 : 44
Number of mobiles sold in the month of October
= 75000 × 22/100
= 750 × 22 = 16500
Total number of mobiles of Vivo sold/during the month of October
= 16500 × 8/25
= 660 × 8 = 5280
Total profit = 5280 × 517
= 2729760
Let ‘A’ be the amount obtained when Rs. 4000 is compounded annually.
Therefore, A = 4000*(1 + (10/100))2
= 4840
C.I. = Rs. (4840 – 4000) = Rs. 840
S.I. = 840/2 = Rs. 420.
Let ‘P’ be the sum of money invested on simple interest.
Therefore, P = (42*100)/(3*8) = 1750
Total marks of 15 students = 73.6 x 15 = 1104
Total marks of 12 students = 73 x 12 = 876
Total marks of Ajay, Akhil and Alok = 1104 – 876 = 228
Suppose Akhil scored A marks, then Alok scored A+6
68 +A+A+ 6 =228
=>A= 77
Let the present age of father and son be m and n years respectively.
According to the question; (m – 3) = 7(n – 3)
=> m – 3 = 7n – 21
=> 7n – m = 18… (1)
Similarly; (m + 3) = 4(n + 3)
=> m + 3 = 4n + 12
=> m – 4n = 9… (2)
From Equation (1) and Equation (2);
=> 3n = 27
=> n = 9
Also we will get m = 45
Let’s assume pipe B was open for “t” minutes.
Hence according to the question:
18/24+t/32=1
=> t/32=1-3/4
=> t/32=1/4
=> t = 8 min
Diameter = 40m, r = 40/2 = 20m
H = 21m
l = √(202+212) = √(400+441) = √841 = 29 m
This post was last modified on August 31, 2018 5:59 pm