Dear Friends, SBI Clerk 2018 Notification has been released we hope you all have started your preparation. Here we have started New Series of Practice Materials specially for SBI Clerk 2018. Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.
Topic | Daily Publishing Time |
Daily News Papers & Editorials | 8.00 AM |
Current Affairs Quiz | 9.00 AM |
Logical Reasoning | 10.00 AM |
Quantitative Aptitude “20-20” | 11.00 AM |
Vocabulary (Based on The Hindu) | 12.00 PM |
Static GK Quiz | 1.00 PM |
English Language “20-20” | 2.00 PM |
Banking Awareness Quiz | 3.00 PM |
Reasoning Puzzles & Seating | 4.00 PM |
Daily Current Affairs Updates | 5.00 PM |
Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
Reasoning Ability “20-20” | 7.00 PM |
English Language (New Pattern Questions) | 8.00 PM |
General / Financial Awareness Quiz | 9.00 PM |
[WpProQuiz 1334]
Click “Start Quiz” to attend these Questions and view Explanation
Directions (Q. 1-5) what value should come in the place of (?) in the following questions:
4). 39 13/17 – 47 18/34 + 23 11/17 – 2 1/34 = ?
5). 44% of 1950 + 82% of 250 + 62% of ? = 7883
Directions (Q. 11-15): What should come in place of question mark (?) in the following number series:
Directions (Q. 16-20): Study the following table carefully and answer the questions given below it. Number of students from various cities, studying in different institutions
Answers:
Directions (Q. 1-5)
7072 ÷ (884 × 16/100) = 30 × 13/12 × ?/39
7072 ÷ 141.44 = 5 × ?/6
50 × 6 = 5 × ?
? = 50 × 6/5
= 60
1478.4/56 + 66.8 × 57 = ? × 3 + 34 × 34.5
26.4 + 3807.6 = ? × 3 + 1173
3834 – 1173 = ? × 3
? × 3 = 2661
? = 887
689 x 6156 ÷ 18% of 684 = 28 x 250 ÷ 8 + ? + 4300
or, 689 x 6156 ÷ 123.12 = 28 × 31.25 + ? + 4300
or, (689x6156x100) / 123.12 = 875 + ? + 4300
= ? + 5175
? = 34450 – 5175 = 29275
4). Answer d
? = 39 13/17 – 47 18/34 + 23 11/17 – 2 1/34
= (39 – 47 + 23 -2) [(13/17) – (18/34) + (11/17) – (1/34)]
= (62 – 49) [(26-18+22-1)/34] = 13 29/34
5). Answer e
44% of 1950 + 82% of 250 + 62% of ? = 7883
Solving by breaking method:
40% of 1950 + 4% of 1950 + (80 + 2)% of 250 + 62% of ? = 7883
or, 780 + 78 + 200 + 5 + 62% of ? = 7883
or, 1063 + 62% of ? = 7883
or, 62% of ? = 7883 – 1063 = 6820
? = (6820/62) x 100 = 11000
Suppose Radha joined the business after x months.
So Radha’s money was invested for (12 – x) months.
(1.5 lakh * 12)/{1 lakh * (12 – x)} = 3/1
=> 18 = 3(12 – x)
=> 3x = 18
=> x = 6 months
Let the present sum of her children’s age be S.
Then Meena’s present age = 3S
Alter 4 years, her age will increase by 4 and the sum of her children’s age increase by 8.
Hence, 3S + 4= 2(S + 8)
3S + 4 = 2S + 16
S = 12
Hence Meena’s present age = 3 x 12 = 36 years
If both filling pipes are working together, portion of the cistern filled in an hour
= 1/14 + 1/16 = (8+7)1112 = 15/112
Hence time taken to fill the cistern = 112/15 hours = 7 7/15 hours = 7 hours 28 minutes.
But due to leak it takes 32 min more.
Hence total time taken = 7 hours 28 minutes + 32 min = 8 hours.
Let the leak take n hours to empty the cistern.
So, 1/14 + 1/16 – 1/n = 1/8.
=> 15/112 – 1/n = 1/8
=› 1/n = 15/112 – 1/8 = 1/112
Hence the cistern will be emptied in 112 hours.
Let the cost of manufacturing be Rs P
Then selling price = P x 1.12 x 1.1 x 1.2 = 1921.92
=> 1.4784P = 1921.92
=> P = 1300
R1 = 132 x 7/(2 x 22) = 21 m
R2 = 176 x 7/(2 x 22) = 28 m
Difference in area = 22/7 x (282 – 212)
= 22/7 x 343 = 1078 sq m
Directions (Q. 11-15):
The series is ×0.5 + 0.5, ×1.5 + 1.5, ×2.5 + 2.5, ×3.5 + 3.5, ×4.5 + 4.5
The series is ×2-1, ×3-2, ×4-3, ×5-4, ×6-5
The whole series is /2 + 1, /3 + 3, /4 + 5, /5 + 7…
The series is +3 × 2, +3 × 6, +3 × 18, +3 × 54, +3 × 162
The whole series is ×0.5 + 4
Directions (Q. 16-20):
Required average = (950+ 800 + 910 + 920 +1090 +820)/6 = 5490/6 = 915
Required percent = 480 -280 / 280 × 100
= 200/280 × 100 = 71.42%
Required ratio = 260: 390 = 2: 3
Total number students in Bangalore = 2910
Total number of students in Mumbai = 3990
Hence, required difference = 3990 – 2910 = 1080
The number of students studying in institute A in Chennai and Hyderabad is, 680 + 980 = 1660
The number of students in institute C in Bangalore and Hyderabad is, 900+1100 = 2000
Required percent = (2000 – 1660)/ 2000 × 100 = 340/ 2000 × 100 = 17%
This post was last modified on August 31, 2018 5:59 pm