Dear Friends, SBI Clerk 2018 Notification has been released we hope you all have started your preparation. Here we have started New Series of Practice Materials specially for SBI Clerk 2018. Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.
Topic | Daily Publishing Time |
Daily News Papers & Editorials | 8.00 AM |
Current Affairs Quiz | 9.00 AM |
Logical Reasoning | 10.00 AM |
Quantitative Aptitude “20-20” | 11.00 AM |
Vocabulary (Based on The Hindu) | 12.00 PM |
Static GK Quiz | 1.00 PM |
English Language “20-20” | 2.00 PM |
Banking Awareness Quiz | 3.00 PM |
Reasoning Puzzles & Seating | 4.00 PM |
Daily Current Affairs Updates | 5.00 PM |
Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
Reasoning Ability “20-20” | 7.00 PM |
English Language (New Pattern Questions) | 8.00 PM |
General / Financial Awareness Quiz | 9.00 PM |
[WpProQuiz 1437]
Click “Start Quiz” to attend these Questions and view Explanation
Directions (Q. 6-10): What should come in place of question mark (?) in the following number series?
Directions (Q. 11-15): What approximate value should come in place of question mark (?) in the following questions?
Directions (Q. 16 – 20): Study the following pie chart carefully to answer the questions below:
Percentage of students passed in different subjects (Total student = 8000)
Percentage of girls passed in these subjects out of the total students. (Total number of girls = 5000)
16). Find the pass percentage of boys in English?
17). How many boys are passed in Science and Social together?
18). Find the average number of girls passed in Hindi, Maths and Science together?
19). Number of boys passed in Hindi is what per cent less than the number of Girls passed in Science?
20). What is the respective ratio of number of boys passed in English to the number of boys passed in Social?
e. None of these
Answers:
Amount = P(1+(r/100))n
12597.12 = 10000(1+(r/100))3
((100+r)/100)3 = 12597.12/10000
((100+r)/100)3 = 1259712/1000000
((100+r)/100)3 = (108/100)3
((100+r)/100) = 108/100
100+r =108
R= 8%
Let Sri’s amount be x,
Saratha now having the amount of 700,
=>(x*(50/100)*(2/5)) – 200 = 700
= > x*(50/100)*(2/5) = 900
= > x= 900*5 = 4500
Sri initially having an amount of Rs. 4500
Total kg’s of 2 types of tea is not given. But the ratio will be 3:4. Take that as, 3x and 4x
Cost price = 3x*140 + 4x*160 = 1060x
Selling price = 7x*170 = 1190x
Profit % = (130x/1060x)*100 = 1300/106
Profit % = 12.26 % = 12% (approx)
Mahesh one day work = 1/24
4 days work = 4/24 = 1/6
Remaining work = 1-(1/6) = 5/6
Naren alone finishes the remaining work in 25 days.
= > (5/6) * Naren’s whole work = 25
= > Naren’s whole work = 30 days
Mahesh and Naren’s one day work,
= > (1/24) + (1/30)
= > 3/40
Both Mahesh and Naren’s together complete the work in,
= > 40/3 days
Directions (Q. 6-10):
The pattern is, +02, -52, +102, -152, +202
The answer is, 422
The pattern is, -(1*7), -(2*7), -(3*7), -(4*7),..
The answer is, 202
The pattern is, *1+22, *2+32, *3+ 42, *4+ 52, *5+ 62,..
The answer is, 1741
The difference of difference is, 4, 8, 12, 16…
The answer is, 188
The difference is, 33 +1, 43 +1, 53 +1, 63 +1, 73 +1
The answer is, 807.
Directions (Q. 11-15):
(18 × 25)/30 = x – 523
15 = x – 523
X= 15+523 = 538
49 × 20 – 25 × 14 = (36 + x) × 9
980 – 350 = 324 +9x
9x = 980 – 350 – 324
9x = 306
X = 34
(262 – 172)/ ? = 21
676 – 289)/x = 21
387/x = 21
X = 387/21 = 18.42
X=18
35 × 16 + 29 × 45 = 41x +468 + 774 -200
560 + 1305 -468 -774+200 = 41x
823 = 41x
X = 823/41
X = 20
(26/5)*190 + (44/7)* 231 = 5x +857
988 + 1452 – 857 = 5x
1583 = 5x
X = 1583/5 = 317
Directions (Q. 16 – 20):
16). Answer b
Total students for English = 0.14*8000=1120
Total girls passed in English=0.14*5000=700
Total boys passed in English=1120-700=420
Boys pass %= (420/1120)*100= 37.5%
17). Answer d
Total Boys passed in Science = [(0.20*8000)-(0.25*5000)] =350
Total Boys passed in Social = [(0.21*8000)-(0.20*5000)] =680
Total boys are passed in Science and Social = 350+680 = 1030
18). Answer c
Total number of girls passed in Hindi, Maths and Science =5000*(66/100)
Average no of girls passed in Hindi, Maths and Science= 5000*(66/100)*(1/3)
= >1100
19). Answer d
Total number of boys passed in Hindi = [(0.20*8000)-(0.20*5000)]= 600
Total number of Girls passed in Science = [0.25*5000]= 1250
Required % = [(1250-600)/1250]*100 = 52%
20). Answer a
Total boys passed in English = (0.14*8000)-(0.14*500)=420
Total Boys passed in Social = [(0.21*8000)-(0.20*5000)] =680
Ratio = 420:680 = 21:34
This post was last modified on August 31, 2018 5:59 pm