“20-20” Quantitative Aptitude | Crack SBI Clerk 2018 Day-41

Dear Friends, SBI Clerk 2018 Notification has been released we hope you all have started your preparation. Here we have started New Series of Practice Materials specially for SBI Clerk 2018. Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.

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1. A circular road runs around a circular ground. If the radius of the ground is 5.5 m and the difference between the circumference of the outer circle and that of the inner circle is 110m, then the area of the road is?

1. 1354.25 m²
2. 1678.75 m²
3. 1567.50 m²
4. 2119.25 m²
5. None of these

2. Ravi spends 30% of his monthly income on food and 20% on the education for his children. Of the remaining salary, he spends 25% on entertainment and 15% on conveyance. He is now left with Rs. 12,336. What is the monthly salary of Ravi?

1. Rs. 27,600
2. Rs. 28,750
3. Rs. 41,120
4. Rs. 33,200
5. None of these

3. The ratio of A and B’s salary is 5:7. If B’s salary is increased by 35%, then his salary becomes 28350. What is the salary of A?

1. 15000
2. 18000
3. 21000
4. 28000
5. None of these

4. In a mixture of 50 litres, the ratio of milk to water is 3:2. If this ratio is to be 5:7, then what is the quantity of water needed to be added?

1. 14 litres
2. 18 litres
3. 24 litres
4. 22 litres
5. None of these

5. The ratio of ages of Sandra and Santhosh is 9:4. After 10 years, Santhosh would be the same as present age of Sandra, find the present age of Sandra.

1. 8 years
2. 18 years
3. 14 years
4. 20 years
5. None of these

Directions (Q. 6-10): What should come in place of question mark in the following questions?

6. √ (14² + 625 ÷25 + 42 × 3 + 229) = x

1. 18
2. 10
3. 28
4. 24
5. None of these

7. 69 % of 730 + 409.3 + 25 % of ? = 1923

1. 4040
2. 3150
3. 2250
4. 3780
5. None of these

8. (1.96)⁴ ÷ (2744 ÷ 1000)³ × (0.14 × 10)³ = (1.4)^{? -2}

1. 5
2. 4
3. 7
4. 6
5. None of these

9. 65 % of (3/17) of (68/177) of (4/5) of 41325 = ?

1. 1456.88
2. 2134.48
3. 2842.28
4. 3124.68
5. None of these

10. 4 5/8 + 6 ¾ – 7 1/8 = x – 2 ¼

1. 5 ¾
2. 7 5/6
3. 6 ½
4. 4 3/8
5. None of these

Directions (Q. 11-15): The following series are based on a specific pattern. Find the next number following the pattern.

11. 88, 92, 128, 176, 326, 506,?

1. 789
2. 898
3. 634
4. 920
5. None of these

12. 5, 5, 8, 16, 31, ?

1. 46
2. 78
3. 89
4. 55
5. None of these

13. 5, 18, 86, 156, ?

1. 212
2. 256
3. 174
4. 328
5. None of these

14. 12, 18, 45, ? , 708.75

1. 96
2. 107.5
3. 189.5
4. 157.5
5. None of these

15. 2, 14, 42, 92, 170, ?

1. 282
2. 316
3. 478
4. 198
5. None of these

Directions (Q. 16–20): The following bar chart shows the percentage distribution of production of bikes by Hero Honda in different plants of the company in different cities, while table shows the percentage distribution of production of different models in each plant.

Study these graphs carefully and answer the following questions

(Total production = 78 lacs)

16. What is the respective ratio of number of model 2 bikes produced in Gurugram to the model 2 bikes in Dharuhera and Alwar together?

1. 161 : 175
2. 169 : 175
3. 171 : 175
4. 181 : 175
5. None of these

17. Find the total number of model 2 bikes produced in all plants together?

1. 22, 25, 340
2. 22, 28, 540
3. 24, 26, 360
4. 22, 24, 460
5. None of these

18. Find the difference between total bikes produced in Alwar plant to the total production of model 2 bikes in all plants together.

1. 509340
2. 540520
3. 409560
4. 222620
5. None of these

19. Model 2 bikes produced in Alwar is what percent of model 2 cars produced in Manesar? (round of to 2 decimal places)

1. 21.41%
2. 22.42%
3. 23.43%
4. 24.44%
5. None of these

20. Find the difference between total bikes produced in Dharuhera, Gugugram and Manesar together and in Haridwar, Alwar and Jaipur together.

1. 708000
2. 802000
3. 790400
4. 772000
5. None of these

Answers:

1. Answer c

Radius of the ground (r) = 5.5 m

The difference between the circumference of the outer circle and that of the inner circle is 110m

= > 2πR- 2πr = 110

= > 2*(22/7)*(R-r) = 110

= > R-r = 17.5

= > R- 5.5= 17.5

= > R= 23 m

The area of the road is,

=> πR² – πr²

=> (22/7) (23² – 5.5²)

= > (22/7) (23+5.5) (23-5.5)

= > (22/7)*28.5* 17.5

= > 1567.5 m²

2. Answer c

Let Ravi’s monthly salary be x,

According to the question,

X*(50/100)*(60/100) = 12336

X = 41120

3. Answer a

The ratio of A and B’s salary is 5:7(5x, 7x)

According to the question,

7x*(135/100) = 28350

X= 28350*(100/ (135*7))

X= 3000

A’s salary = 5x = 15000

4. Answer d

Total Quantity = 50 litres

The ratio of milk to water= 3:2

Milk= 30 litres, Water= 20 litres

According to the question,

30/(20+x) = 5/7

42 = 20+x

X= 22 litres

So 22 litres of water should be added.

5. Answer b

The ratio of ages of Sandra and Santhosh is 9:4

Let the Present ages of Sandra and Santhosh be 9x, 4x.

According to the question,

4x+10 = 9x

5x = 10

X= 2

Sandra’s Present age= 9x = 18 years

Directions (Q. 6-10):

6. Answer d

√ (196+ 25+126+ 229) =x

X= √576

X= 24

7. Answer a

= > (69/100)*730 +409.3 + (25/100)*x = 1923

= > 503. 7 + 409. 3 + (1/4)*x = 1923

= > (1/4)*x = 1923 – 503. 7 – 409. 3

= > (1/4)*x = 1010

= > x = 4040

8. Answer b

((1.4)²)⁴ ÷ ((1.4)³)³ × (1.4)³ = (1.4)^{x -2}

(1.4)⁸ ÷ (1.4)⁹ × (1.4)³ = (1.4)^{x -2}

(1.4)^8-9+3 = (1.4)^{x -2}

(1.4)² = (1.4)^{x -2}

2 = x-2

X= 4

9. Answer a

(65/100) × (3/17) × (68/177) × (4/5) × 41325 = x

X = 85956/ 59

X = 1456.88

10. Answer c

4 5/8 + 6 ¾ – 7 1/8 + 2 ¼ = x

(4+6-7 +2) (5/8 +3/4 -1/8 + ¼) = x

5 (3/ 2) = x

X= (5+1) ((3-2)/2)

X = 6 ½

Directions (Q. 11-15):

11. Answer b

The pattern is, + (2³ – 2²), + (3³+ 3²), + (4³ – 4²), + (5³ + 5²), + (6³ – 6²),

+ (7³ + 7²)..

The answer is, 898

12. Answer d

The difference of difference is, 3, 5, 7, 9

The answer is, 55

13. Answer c

The pattern is, ×6 -12, ×4 +14, ×2-16, ×1 +18

The answer is, 174

14. Answer d

The pattern is, *3/2, *5/2, *7/2, *9/2

The answer is, 157.5

15. Answer a

The pattern is, 1² × 3 – 1, 2² × 4 – 2, 3² × 5 – 3, 4² × 6 – 4, 5² × 7 – 5, 6² × 8 – 6.

The answer is, 282

Directions (Q. 16–20):

16. Answer b

Required ratio = [(26/100) * (13/100) * 78] : {[(10/100) * (13/100)] + [(22/100) * (10/100)] * 78}

= 169 : 175

17. Answer a

Model 2 cars produced in Dharuhera plant = 10/100 * 13/100 * 78 = 1.0140 lacs = 101400

In Gurugram plant = 13/100 * 26/100 * 78 = 2.6364 lacs = 263640

In Manesar plant = 18/100 * 50/100 * 78 = 702000

In Haridwar Plant = 20/100 * 10/100 * 78 = 468000

In Alwar Plant = 22/100 * 10/100 * 78 = 171600

In Jaipur Pant = 8/100 * 55/100 * 78 = 343200

In Noida Plant = 9/100 * 25/100 * 78 = 175500

Total production of Model 2 bikes = 2225340

18. Answer a

Total bikes produced in Alwar = 22/100 * 78 = 17.16 lac or 1716000

Total model 2 bikes produced = 2225340

Required difference = 509340

19. Answer d

Required percentage = [(22/100) * (10/100) * 78]/[(18/100) * (50/100) * 78)] * 100 = 24.44%

20. Answer e

Required difference = [(10 + 13 + 18) % – (20 + 22 + 8) %] of 78 lacs

= 7.02 lacs = 702000

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