Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for SBI PO 2019 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
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1) The ratio of length and breadth of the rectangle is 3: 2 and the area of the rectangle is 216 Sq m. Find the perimeter of square, whose side is 4 meter less than the breadth of the rectangle?
a) 48 Sq m
b) 54 Sq m
c) 36 Sq m
d) 32 Sq m
e) None of these
2) A, B and C entered into a partnership by investing Rs. 35000, Rs. 45000 and Rs. 60000 respectively. After 4 months, A withdraws two-fifth of the amount and B invested Rs. 15000 more. After another 3 months C withdraw three-fifth of the amount. Find the total profit at the end of the year, if the share of B is Rs. 49500?
a) Rs. 122450
b) Rs. 113100
c) Rs. 134520
d) Rs. 158760
e) None of these
3) The Average marks obtained by 56 students in an examination is 15. If the average marks of passed students are 18 and that of failed students are 11, then find the number of students who failed the examination?
a) 28
b) 24
c) 44
d) 34
e) None of these
4) The sum of twice the age of Abinav and his father is 107 and the sum of twice the age of his father and Abinav is 136. The average age of Abinav and his father and mother is 43. Then find the present age of Abinav’s mother?
a) 36 years
b) 32 years
c) 44 years
d) 48 years
e) None of these
5) A, B and C can do a piece of work in 15 days, 18 days and 24 days respectively. They started work together, but after 5 days A left the work, B left the work 6 days before the completion of the work. In how many days the work gets completed?
a) 10 2/7 days
b) 8 4/5 days
c) 9 3/8 days
d) 11 5/6 days
e) None of these
Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:
There are 3 departments A, B and C in a company. Total number of employees in all the given departments is 7000. The ratio of total employees in 3 departments A, B and C is 14 : 12 : 9. Some of the employees from these departments are managers. The female employee is always greater than male employee including managers also.
In department A, the difference between the male to that of female employees is 400. Out of the total employees in this department, 12 % are managers. Total male managers are 154.
In department B, the total number of female employees is 200 more than the total male employees in department A. Out of the total employees, the percentage of total number of managers in department B and C is 15 % and 33 1/3 % respectively. The difference between the male managers to that of female managers is 112.
In department C, the total female employees is same as total male employees in department B. Total female managers in department C is twice of total female managers in department A.
6) Total female employees in department A is what percentage of total male employees in department B?
a) 180 %
b) 125 %
c) 160 %
d) 140 %
e) None of these
7) Find the ratio between the total male employees in department A and C together to that of total female managers in department B and C together?
a) 10 : 3
b) 16 : 5
c) 21 : 8
d) 17 : 7
e) None of these
8) Find the difference between the total male managers in department A to that of total female managers in department C?
a) 260
b) 210
c) 180
d) 150
e) None of these
9) Find the average number of managers in all the given departments together?
a) 375
b) 360
c) 408
d) 432
e) None of these
10) Total male managers in department A and B together is what percentage of total male employees in department C?
a) 34.75 %
b) 42.25 %
c) 25.5 %
d) 38.5 %
e) None of these
Answers :
1) Answer: d)
The ratio of length and breadth of the rectangle = 3 : 2 (3x, 2x)
The area of the rectangle = 216 Sq m
3x * 2x = 216
6x2 = 216
x2 = 36
x = 6
Breadth of the rectangle = 2x = 12 m
Side of the square = 12 – 4 = 8 m
Perimeter of Square = 4a = 32 Sq m
2) Answer: b)
The ratio of share of A, B and C,
= > [35000*(4) + 35000*(3/5)*8] : [45000*4 + 60000*8] : [60000*7 + 60000*(2/5)*5]
= > 308000 : 660000 : 540000
= > 77: 165 : 135
165’s = 49500
1’s = 300
Total profit = 377’s = 377*300 = Rs. 113100
3) Answer: b)
Let the number of passed students be x,
56 * 15 = 18x + (56 – x) * 11
840 = 18x + 616 – 11x
224 = 7x
X = 224/7 = 32
Total number of failed students = 56 – x = 24
Shortcut:
= > 4 : 3
7’s = 56
1’s = 8
Total number of failed students = 3’s = 24
4) Answer: d)
Let the age of Abinav and his father be x and y,
2x + y = 107 —Ã (1)
X + 2y = 136 —Ã (2)
By solving (1) and (2),
Y = 55, X = 26
The average age of Abinav and her father and mother = 43
Sum of the ages of Abinav and her father and mother = 43*3 = 129
Present age of Abinav’s mother = 129 – (55 + 26) = 48 years
5) Answer: a)
According to the question,
Work done by in A, B and C,
(5/15) + [(x – 6)/18] + (x/24) = 1
(1/3) + [(x – 6)/18] + (x/24) = 1
[(x – 6)/18] + (x/24) = 1 – (1/3) [(x – 6)/18] + (x/24) = 2/3(4x – 24 + 3x)/72 = 2/3
7x – 24 = 48
7x = 72
X = 72/7 = 10 2/7 days
Directions (Q. 6 – 10):
Total employees = 7000
Total employees in department A = 7000*(14/35) = 2800
Total employees in department B = 7000*(12/35) = 2400
Total employees in department C = 7000*(9/35) = 1800
In department A,
X + y = 2800 –Ã (1)
X – y = 400 –à (2)
Here X – female employees, because a female employee is greater than male employee.
Solving (1) and (2), we get,
Female employees = 1600, Male employees = 1200
Total managers = 2800*(12/100) = 336
Total male managers = 154
Total female managers = 336 – 154 = 182
In department B,
Total female employees = 200 + 1200 = 1400
Total male employees = 2400 – 1400 = 1000
Total managers = 2400*(15/100) = 360
M + N = 360 –Ã (1)
M – N = 112 –à (2)
Here M – Female managers, N – Male managers
Female managers (M) = 236
Male managers (N) = 124
In department C,
Total female employees = 1000
Total male employees = 1800 – 1000 = 800
Total managers = 1800*(1/3) = 600
Total female managers = 2*182 = 364
Total male managers = 600 – 364 = 236
| Dept | Total employees | Male | Female | Total managers | Male managers | Female managers |
| A | 2800 | 1200 | 1600 | 336 | 154 | 182 |
| B | 2400 | 1000 | 1400 | 360 | 124 | 236 |
| C | 1800 | 800 | 1000 | 600 | 236 | 364 |
6) Answer: c)
Total female employees in department A = 1600
Total male employees in department B = 1000
Required % = (1600/1000) * 100 = 160 %
7) Answer: a)
The total male employees in department A and C together
= > 1200 + 800 = 2000
The total female managers in department B and C together
= > 236 + 364 = 600
Required ratio = 2000 : 600 = 10 : 3
8) Answer: b)
The total male managers in department A = 154
The total female managers in department C = 364
Required difference = 364 – 154 = 210
9) Answer: d)
The average number of managers in all the given departments together
= > (336 + 360 + 600)/3
= > 1296/3 = 432
10) Answer: a)
Total male managers in department A and B together
= > 154 + 124 = 278
Total male employees in department C = 800
Required % = (278/800)*100 = 34.75 %
