Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for SBI PO 2019 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
[WpProQuiz 6328]
Click Here to View Quantitative Aptitude Questions in Hindi
Directions (Q. 1 – 5): What value should come in place of (?) in the following questions?
1) (11/110) of 54330 + 6.5 ÷ 13 × 280 – 31 × 5 = ?
a) 5418
b) 5952
c) 4276
d) 4534
e) None of these
2) 1680 ÷ ? + 173 × 2 = 642 – 256 + 25 % of 400
a) 18
b) 23
c) 15
d) 12
e) None of these
3) (242 – 112) × 8 ÷ 26 + ? % of 250 = 196
a) 28
b) 22.4
c) 19.6
d) 33
e) None of these
4) ? % of (√144) × 25 + 390 = 453
a) 28
b) 32
c) 21
d) 17
e) None of these
5) (8/11) of [956 – 373] + 286 = ? – 1125
a) 1835
b) 2156
c) 2278
d) 1543
e) None of these
Directions (6 – 10): Study the following information carefully and answer the questions given below.
Following two pie chart show the information about total number of employees and total number of male employees in 5 different companies respectively.
6) If the ratio of females who are under graduate and post graduate in company B and C is 7: 8 and 13: 8 respectively, total number of females who are post graduate in those company is approximately what percentage of number of males in those company?
a) 37%
b) 23%
c) 25%
d) 29%
e) 27%
7) Find the ratio between the average number of female in company A, D and E together to the number of employees in E.
a) 1: 2
b) 2: 3
c) 3: 7
d) 2: 9
e) 1: 9
8) Find the impact on total number of employees in company C and D, if the number of males in company C and D increased by 50%.
a) 28% increase
b) 32% increase
c) 35% increase
d) 56% increase
e) 15% increase
9) Find the ratio between the sum of the 15% of male employees in company A and 18% of female employees in company B and the sum of total employees in C and the number of male employees in D.
a) 26: 5
b) 2: 15
c) 3: 13
d) 3: 26
e) 15: 7
10) What is the difference between the central angle made by the employees of A, C and E and the number of females in company C, D and E, if the total number of females are put in a pie chart?
a) 46.8°
b) 36.5°
c) 56.2°
d) 24.9°
e) 85.6°
Answers :
1) Answer: a)
(11/110)*54330 + (6.5/13)* 280 – 31*5 = x
5433 + 140 – 155 = x
X = 5418
2) Answer: d)
(1680/x) + 173*2 = 642 – 256 + (25/100)*400
(1680/x) = 642 – 256 + 100 – 346
(1680/x) = 140
X = 12
3) Answer: b)
[(24 + 11) (24 – 11)] × 8 ÷ 26 + (x/100)*250 = 196(35*13*8)/26 + (5x/2) = 196
140 + (5x/2) = 196
(5x/2) = 196 – 140
5x/2 = 56
X = (56*2)/5 = 22.4
4) Answer: c)
(X/100)*12*25 + 390 = 453
3x = 453 – 390
3x = 63
X = 63/3 = 21
5) Answer: a)
(8/11)*583 + 286 = x – 1125
424 + 286 + 1125 = x
X = 1835
Directions (6 – 10):
6) Answer: e)
In B,
Total number of employees = 23/100 * 1800 = 414
Number of males = 22/100 * 1200 = 264
Number of females = 414 – 264 = 150
Number of females who are post graduate = 150/15 * 8 = 80
In C,
Total number of employees = 19/100 * 1800 = 342
Number of males = 18/100 * 1200 = 216
Number of females = 342 – 216 = 126
Number of females who are post graduate = 126/21 * 8 = 48
Required % = [(80 + 48)/(264 + 216)] * 100 = 128/480 * 100 = 26.667% = 27%
7) Answer: d)
In A,
Total number of employees = 14/100 * 1800 = 252
Number of males = 20/100 * 1200 = 240
Number of females = 252 – 240 = 12
In D,
Total number of employees = 17/100 * 1800 = 306
Number of males = 17/100 * 1200 = 204
Number of females = 306 – 204 = 102
In E,
Total number of employees = 27/100 * 1800 = 486
Number of males = 23/100 * 1200 = 276
Number of females = 486 – 276 = 210
Required ratio = [(12 + 102 + 210)/3]: 486
= 2: 9
8) Answer: b)
In D,
Total number of employees = 17/100 * 1800 = 306
Number of males = 17/100 * 1200 = 204
50% of males = 102
In C,
Total number of employees = 19/100 * 1800 = 342
Number of males = 18/100 * 1200 = 216
50% of males = 108
Total increase = 210
% of increase = (210/(342 + 306)) * 100 = 32.40% = 32%
9) Answer: d)
In A,
Number of males = 20/100 * 1200 = 240
15% of males =240 * 15/100 = 36
In B,
Total number of employees = 23/100 * 1800 = 414
Number of males = 22/100 * 1200 = 264
Number of females = 414 – 264 = 150
18% of females = 150 * 18/100 = 27
In D,
Number of males = 17/100 * 1200 = 204
In C,
Total number of employees = 19/100 * 1800 = 342
Required ratio = (36 + 27): (342 + 204) = 3: 26
10) Answer: a)
In A,
Total number of employees = 14/100 * 1800 = 252
In C,
Total number of employees = 19/100 * 1800 = 342
Number of males = 18/100 * 1200 = 216
Number of females = 342 – 216 = 126
In D,
Total number of employees = 17/100 * 1800 = 306
Number of males = 17/100 * 1200 = 204
Number of females = 306 – 204 = 102
In E,
Total number of employees = 27/100 * 1800 = 486
Number of males = 23/100 * 1200 = 276
Number of females = 486 – 276 = 210
Total female employees = 1800 – 1200 = 600 = 360°
Total female employees in C, D and E = 126 + 102 + 210 = 438
Angle made by female employees in C, D and E = (360 * 438)/600
= 262.8°
Angle made by employees in A, C and E = [(14 + 19 + 27)/100] * 360
= 216°
Required difference = 262.8° – 216°
= 46.8°
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SBI PO Prelims Quantitative Aptitude Questions 2019 (Day-42)
This post was last modified on October 25, 2021 2:31 pm