Dear Readers, Bank Exam Race for the Year 2018 is already started, To enrich your preparation here we have providing new series of Practice Questions on Quantitative Aptitude – Section. Candidates those who are preparing for NIACL AO Prelims 2018 Exams can practice these questions daily and make your preparation effective.
[WpProQuiz 4747]
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1) If 5 men or 6 women or 8 boys can finish a work in 120 days working 8 hours a day. The number of days taken by 10 men, 6 women and 12 boys working 12 hours a day will be?
a) 15 2/7 days
b) 14 7/8 days
c) 16 2/5 days
d) 17 7/9 days
e) None of these
2) A 200 liter mixture of milk and water contains milk and water in the ratio of 7 : 3. How much milk should be added to the mixture to get a new mixture of milk and water in the ratio of 13 : 5?
a) 12 litres
b) 14 litres
c) 16 litres
d) 18 litres
e) None of these
3) Find the respective ratio of the volumes of a sphere and a cylinder, both having radius 14 cm and height of the cylinder is 16 cm?
a) 5 : 8
b) 7 : 6
c) 6 : 7
d) 8 : 5
e) None of these
4) The difference between Simple interest and Compound interest on a certain sum at the rate of 20% per annum for two years is Rs. 1680. Find the simple interest on that sum at the rate of 14% per annum after 8 years?
a) Rs. 44040
b) Rs. 47340
c) Rs. 45040
d) Rs. 47040
e) None of these
5) The ratio of present ages of a husband and wife is 7 : 5. After 10 years, the ratio of their ages will be 9 : 7. A child was born after 2 years of their marriage, then find the age of child if the ratio of ages at the time of marriage was 5 : 3?
a) 12 years
b) 10 years
c) 14 years
d) 8 years
e) None of these
Directions (Q. 6 – 10) Study the following information carefully and answer the given questions:
The following table shows the ratio of students passed from different streams in graduation from different city and also the ratio of males and females among them.
6) If the total number of males who passed in B. Sc from City R is 1275, then find the total number of students passed in B. A from City R?
a) 2380
b) 3256
c) 2178
d) 3384
e) None of these
7) If the total number of females who passed in B. A from City P is 1113, then find the difference between the total number of students passed in B.A and that of B. Sc in City P?
a) 1094
b) 2180
c) 1986
d) 1272
e) None of these
8) If the total number of students passed from City S is 2794, then the total number of females passed in B. A from City S is what percentage of total number of males passed in B. Sc from City S?
a) 115 %
b) 72 %
c) 100 %
d) 88 %
e) None of these
9) The number of females who passed in B. A from City Q is approximately more/less than the number of males who passed in B. A from City Q?
a) 173 % less
b) 167 % more
c) 152 % less
d) 173 % more
e) 167 % less
10) The number of students passed in B. A from City T is 1716. Find the ratio between the total number of females who passed in B. A from City T to that of total number of males who passed in B. Sc from City T?
a) 1287 : 572
b) 1331 : 557
c) 1089 : 452
d) 956 : 369
e) None of these
Answers:
1) Answer: d)
5 men = 6 women
6 women = 8 boys
10 men, 6 women and 12 boys = 12 women + 6 women + 9 women = 27 women
Women                      days               hours
6Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 120Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 8
27                              x                     12
(6*120*8) = (27* x days *12)
X = (6*120*8) / (27*12) = 160/9 = 17 7/9 days
2) Answer: c)
Milk in the mixture = 200*(7/10) = 140 liters
Water in the mixture = 200 – 140 = 60 liters
Let the amount of milk be added be x,
(140 + x)/60 = 13/5
700 + 5x = 780
5x = 80
x = 16 liters
3) Answer: b)
Volume of the sphere = (4/3)*Ï€r3 = (4/3)*(22/7)*14*14*14
Volume of the cylinder = πr2h = (22/7)*14*14*16
Required ratio = [(4/3)*(22/7)*14*14*14] : [(22/7)*14*14*16] = 7 : 6
4) Answer: d)
The difference between CI and SI for two years is,
Difference = P*(r/100)2
= > 1680 = P*(20/100)2
= > 1680 = P*(1/5)2
= > 1680 = P*(1/25)
= > P = Rs. 42000
SI = (42000*14*8)/100 = Rs. 47040
5) Answer: d)
Let the ratio of their present age be 7x and 5x respectively,
(7x + 10) / (5x + 10) = 9 / 7
49x + 70 = 45x + 90
4x = 20
X = 5
Age of husband = 35 years
Age of wife = 25 years
Let their marriage be held y years ago,
So,
(35 – y) / (25 – y) = 5 / 3
105 – 3y = 125 – 5y
2y = 20
Y = 10 years
Age of the child = 10 – 2 = 8 years
6) Answer: a)
The total number of males who passed in B. Sc from City R= 1275
3’s = 1275
1’s = 425
Total number of students passed in B. Sc from City R = 7’s = 2975
Total number of students passed in B. A from City R = 2975*(4/5) = 2380
7) Answer: d)
The total number of females who passed in B. A from City P = 1113
7’s = 1113
1’s = 159
Total number of students passed in B. A from City P = 159*12 = 1908
Total number of students passed in B. Sc from City P = 1908*(5/3) = 3180
Required difference = 3180 – 1908 = 1272
8) Answer: c)
The total number of students passed from City S = 2794
11’s = 2794
1’s = 254
The total number of students passed in B. A from City S = 1270
The total number of students passed in B. Sc from City S = 1524
The total number of females passed in B. A from City S
= > 1270*(3/5) = 762
The total number of males passed in B. Sc from City S
= > 1524*(1/2) =762
Required % = (762/762)*100 = 100 %
(Or)
The total number of females passed in B. A from City S = 5x*(3/5) = 3x
The total number of males passed in B. Sc from City S = 6x*(1/2) = 3x
Required % = (3x/3x)*100 = 100 %
9) Answer: b)
The ratio of total number of male to female students passed in B. A in City Q
= > 3 : 8
Required % = [(8x – 3x)/3x]*100 = (5x/3x)*100 = 166.67 % = 167 % more
 10) Answer: a)
The number of students passed in B. A from City T = 1716
6’s = 1716
1’s = 286
The number of students passed in B. Sc from City T = 1430
The total number of females who passed in B. A from City T
= > 1716 *(3/4) = 1287
The total number of males who passed in B. Sc from City T
= > 1430 *(2/5) = 572
Required ratio = 1287 : 572
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| Topic | Daily Publishing Time |
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| Current Affairs Quiz | 9.00 AM |
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