Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for IBPS Clerk Prelims 2019 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
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Data Interpretation
Directions (1 – 6): Study the following information carefully and answer the questions given below.
The given table shows the number of students in four different colleges in four different departments.
1) If the ratio of the number of students of CSE from A to C is 21:32, find the number of ME students from C?
a) 380
b) 360
c) 340
d) 320
e) None of these
2) Total number of EEE students from all the colleges together is 1900, then what is the number of ME students from B?
a) 420
b) 460
c) 440
d) 480
e) None of these
3) If the ratio of the number of ME students from B to C is 24: 19, what is the number of CSE students from C?
a) 580
b) 600
c) 620
d) 660
e) None of these
4) If the total number of students from A is equal to the total number of ME students from all the colleges together. The number of ECE students from C is approximately what percent of the total number of students from A all the departments together?
a) 18%
b) 20%
c) 22%
d) 24%
e) None of these
5) If the average number of ECE students from all the colleges together is 430 and the number of ECE students from D is equal to the number of ME students from A. What is the ratio of the number of ECE students from A to the number of CSE students from D?
a) 7: 8
b) 8: 9
c) 5: 6
d) 4: 3
e) None of these
6) What is the difference between the number of EEE and ME students from B together and the number of CSE and ME students from C together?
a) 180
b) 200
c) 220
d) 140
e) 160
Missing number series
Directions (7 – 10): What value should come in the place of (?) in the following number series?
7) 4, 6, 18, 66, 284, ?
a) 360
b) 972
c) 1280
d) 1450
e) 1620
8) 12, 22, 38, ?, 101.5, 160.25
a) 63
b) 65
c) 67
d) 69
e) 71
9) 18, 54, 79, 95, 104, ?
a) 110
b) 106
c) 108
d) 112
e) 114
10) 995, 723, 505, 335, 207, ?
a) 100
b) 105
c) 110
d) 115
e) 120
Answers :
Directions (1-6) :
1) Answer: a)
Total number of CSE students =2000
Number of CSE students from A and C = 2000 – 580 – 360 = 1060
Number of CSE students from C = 32/53 * 1060 = 640
Number of ME students from C = 2000 – 640 – 540 – 440 = 380
2) Answer: d)
Number of EEE students from B = 1900 – 440 – 540 – 560 = 360
Number of ME students from B = 1700 – 580 – 360 – 280 = 480
3) Answer: e)
Number of ME students from B and C = 2000 – 680 – 460 = 860
Number of ME students from C = 19/43 * 860 = 380
Number of CSE students from C = 2000 – 540 – 440 – 380 = 640
4) Answer: c)
Required percentage = 440/2000 * 100 = 22%
5) Answer: b)
Total number of ECE students = 430 * 4 = 1720
Number of ECE students from D = 680
Number of ECE students from A = 1720 – 280 – 440 – 680 = 320
Required ratio = 320: 360 = 8: 9
6) Answer: a)
Number of EEE and ME students from B = 1700 – 580 – 280 = 840
Number of CSE and ME students from C = 2000 – 540 – 440 = 1020
Difference = 1020 – 840 = 180
Directions (7-10) :
7) Answer: d)
(4 + 2) * 1 = 6
(6 + 3) * 2 = 18
(18 + 4) * 3 = 66
(66 + 5) * 4 = 284
(284 + 6) * 5 = 1450
8) Answer: a)
12 * 1.5 + 4 = 22
22 * 1.5 + 5 = 38
38 * 1.5 + 6 = 63
63 * 1.5 + 7 = 101.5
101.5 * 1.5 + 8 = 160.25
9) Answer: c)
18 + 62 = 54
54 + 52 = 79
79 + 42 = 95
95 + 32 = 104
104 + 22 = 108
10) Answer: d)
103 – 5 = 995
93 – 6 = 723
83 – 7 = 505
73 – 8 = 335
63 – 9 = 207
53 – 10 = 115
This post was last modified on October 27, 2021 9:56 am