Dear Readers, Bank Exam Race for the Year 2018 is already started, To enrich your preparation here we have providing new series of Practice Questions on Quantitative Aptitude – Section. Candidates those who are preparing for IBPS Clerk Prelims 2018 Exams can practice these questions daily and make your preparation effective.
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Directions (Q. 1 – 5) Study the following information carefully and answer the given questions:
The following table shows the percentage of passed girls out of the total passed students in two different colleges in 6 different years.
1) If the total number of boys passed in the year 2012 from college P and college Q is 459 and 342 respectively, then find the total number of girls passed in the year 2012 from both the colleges together?
a) 863
b) 949
c) 752
d) 1017
e) None of these
2) If the total number of students passed in the year 2014 and 2016 from college P and college Q is 900 and 880 respectively, then the total number of boys passed from college P in the year 2014 is approximately what percentage of total number of girls passed from college Q in the year 2016?
a) 128 %
b) 104 %
c) 92 %
d) 145 %
e) 73 %
3) If the total number of students passed from college P in the year 2011 and that from college Q in the year 2013 is same, then find the ratio between the total number of boys passed from college P in the year 2011 to that of total number of girls passed from college Q in the year 2013?
a) 15 : 19
b) 24 : 37
c) 61 : 73
d) 46 : 53
e) None of these
4) If the total number of girls passed from college P in the year 2016 is same as total number of girls passed from college Q in the year 2015 and the total number of students passed from college Q in the year 2015 is 920, then find the total number of students passed from college P in the year 2016?
a) 850
b) 950
c) 900
d) 800
e) None of these
5) Find the average number of girls passed from college Q in the year 2014 and 2016 together, if the total number of students passed from college Q in the year 2014 and 2016 is 850 and 880 respectively?
a) 412
b) 363
c) 457
d) 395
e) None of these
Directions (Q. 6 – 10): Each question contains Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.
6) Quantity I: The SI on a certain sum of money for 5 years at 8 % per annum is Rs. 14000. Then the principle is?
Quantity II: The CI on a certain sum of money for 3 years at 5 % per annum is Rs. 6305. Then the principle is?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
7) Quantity I: 3 years ago, the ratio of age of A and B is 3: 4. After 2 years, the sum of their ages is 45. Then find the present age of A?
Quantity II: 5 years ago, the ratio of age of P and Q is 3: 4. P’s age after 6 years is equal to the present age of Q. Then find the present age of P?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
8) Quantity I: P and Q started a business by Rs. 4500 and Rs. 8000 respectively. P invested for whole year and they divided their shares after a year. The ratio of profit of P and Q is 3 : 4. Then, how many months Q invested the money?
Quantity II: A and B invested in the ratio of 2 : 3. A invested the money for 9 months. The ratio of profit of A and B is 3 : 4. Then, how many months B invested the money?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
9) A box contains 7 white balls, 5 violet balls and 3 yellow balls.
Quantity I: If 3 balls are drawn randomly, then the probability of getting at least one yellow balls?
Quantity II: If 2 balls are drawn randomly, then the probability of getting both the balls is either white or violet?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
10) Quantity I: The ratio between the downstream and upstream speed of the boat is 5: 4. The boat travels 120 km downstream in 6 hours. Find the speed of the boat in still water?
Quantity II: The boat travels 160 km downstream in 8 hours. The speed of the stream is 8 km/hr. Find the speed of the boat in still water?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
Answers :
Direction (1-5) :
1) Answer: b)
The total number of boys passed in the year 2012 from college P = 459
54 % of total students passed from college P in the year 2012 = 459
Total students passed from college P in the year 2012 = 459*(100/54)
Total number of girls passed in the year 2012 from college P
= > 459*(100/54)*(46/100) = 391
The total number of boys passed in the year 2012 from college Q = 342
38 % of total students passed from college Q in the year 2012 = 342
Total students passed from college Q in the year 2012 = 342*(100/38)
Total number of girls passed in the year 2012 from college Q
= > 342*(100/38)*(62/100) = 558
Required total = 391 + 558 = 949
2) Answer: a)
The total number of students passed in the year 2014 from college P = 900
The total number of boys passed from college P in the year 2014
= > 900*(50/100) = 450
The total number of students passed in the year 2016 from college Q = 880
The total number of girls passed from college Q in the year 2016
= > 880*(40/100) = 352
Required % = (450/352)*100 = 128 %
3) Answer: d)
The total number of students passed from college P in the year 2011 = The total number of students passed from college Q in the year 2013 = x
Required ratio = [x*(46/100)] : [x*(53/100)]
= > 46: 53
4) Answer: c)
The total number of girls passed from college P in the year 2016 = The total number of girls passed from college Q in the year 2015
The total number of students passed from college Q in the year 2015 = 920
The total number of girls passed from college Q in the year 2015
= > 920*(45/100) = 414
The total number of girls passed from college P in the year 2016 = 414
(46/100)*Total students passed from college P in the year 2016 = 414
Total students passed from college P in the year 2016 = 414*(100/46) = 900
5) Answer: b)
The total number of students passed from college Q in the year 2014 = 850
Total girls passed from college Q in the year 2014 = 850*(44/100) = 374
The total number of students passed from college Q in the year 2016 = 880
Total girls passed from college Q in the year 2016 = 880*(40/100) = 352
Required average = (374 + 352)/2 = 726/2 = 363
Direction (6-10) :
6) Answer: c)
Quantity I:
SI = (P*n*r)/100
14000 = (P*5*8)/100
P = (14000*100)/40 = Rs. 35000
Quantity II:
C.I = P*[(1 + (r/100))3 – 1]
6305 = P*[(1 + 5/100)3 – 1]
6305 = P*[(105/100)3 – 1]
6305 = P*[(21/20)3 – 1]
6305 = P*[(9261/8000) – 1]
6305 = P*[1261/8000]
P = (6305*8000)/1261 = Rs. 40000
Quantity I < Quantity II
7) Answer: c)
Quantity I:
3 years ago, the ratio of age of A and B = 3: 4 (3x, 4x)
According to the question,
3x + 4x + 10 = 45
7x = 35
X = 5
The present age of A = 3x + 3 = 18 years
Quantity II:
5 years ago, the ratio of age of P and Q = 3: 4 (3x, 4x)
According to the question,
3x + 5 + 6 = 4x + 5
X = 6
The present age of P = 3x + 5 = 18 + 5 = 23 years
Quantity I < Quantity II
8) Answer: a)
Quantity I:
According to the question,
(4500*12)/(8000*x) = (3/4)
X = 9 months
Quantity II:
According to the question,
(2*9)/(3*x) = (3/4)
18/3x = (3/4)
72 = 9x
X = (72/9) = 8 months
Quantity I > Quantity II
9) Answer: a)
Quantity I:
Total probability n(S) = 15C3
Required probability n(E) = 1 – P(none is yellow)
Probability of getting none is yellow balls,
P(E) = n(E)/n(S) = 12C3/15C3
= > 44/91
Required probability = 1 – (44/91) = 47/91
Quantity II:
Total probability n(S) = 15C2
Required probability n(E) = 7C2 or 5C2
P(E) = n(E)/n(S) = 7C2 or 5C2 / 15C2
= > (21 + 10)/105 = 31/105
= > 31/105
Quantity I > Quantity II
10) Answer: a)
Quantity I:
Downstream speed = 120/6 = 20 km/hr
Upstream speed = 20*(4/5) = 16 km/hr
Speed of boat in still water = ½ *(20 + 16) = 18 km/hr
Quantity II:
Downstream speed = 160/8 = 20 km/hr
Downstream speed = Speed of boat in still water + speed of stream
Let the speed of boat be x,
=> x + 8 = 20
=> x = 12 km/hr
Speed of boat in still water = 12 km/hr
Quantity I > Quantity II
Kindly watch this video to know about Important Table Based Data Interpretation for IBPS Clerk Prelims 2018
Daily Practice Test Schedule | Good Luck
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Current Affairs Quiz (Hindi) | 9.30 AM |
| IBPS Clerk Prelims – Reasoning | 10.00 AM |
| IBPS Clerk Prelims – Reasoning (Hindi) | 10.30 AM |
| IBPS Clerk Prelims – Quantitative Aptitude | 11.00 AM |
| IBPS Clerk Prelims – Quantitative Aptitude (Hindi) | 11.30 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| IBPS Clerk Prelims – English Language | 1.00 PM |
| SSC Practice Questions (Reasoning/Quantitative aptitude) | 2.00 PM |
| IBPS Clerk – GK Questions | 3.00 PM |
| SSC Practice Questions (English/General Knowledge) | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| Canara Bank PO Mains – Reasoning | 6.00 PM |
| Canara Bank PO Mains – Quantitative Aptitude | 7.00 PM |
| Canara Bank PO Mains – English Language | 8.00 PM |
