RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-13)

By Valar Mathi - Mar 21 2018

Dear Aspirants, Here we have given the Important RRB ALP & Technicians Exam 2018 Practice Test Papers. Candidates those who are preparing for RRB ALP 2018 can practice these Arithmetic Questions to get more confidence to Crack RRB 2018 Examination.

[WpProQuiz 1610]

Click “Start Quiz” to attend these Questions and view Explanation

  1. The HCF of two numbers “a” and “b” is 18. What can be the LCM of “a” and “b”?
  1. 42
  2. 9
  3. 12
  4. None of these
  1. How many pairs of numbers are there such that their HCF and LCM are 12 and 924, respectively?
  1. 1
  2. 2
  3. 3
  4. 4
  1. Ajay cycles at 3 km/h more than his usual speed and reached the destination 60 km away 1 h earlier. What is his usual speed?
  1. 15 km/h
  2. 12 km/h
  3. 25 km/h
  4. 10 km/h
  1. 12 is divided into two parts such that 3 times the first part added to 4 times the second part makes 43. The difference between both parts is
  1. 1
  2. 2
  3. 3
  4. 7
  1. What will be the minimum value of (x – 5) (x – 13)?
  1. – 8
  2. 4
  3. 8
  4. – 16
  1. How many sequences of answers are possible in a test having 12 multiple choice questions if each question has five options?
  1. 60
  2. 12! × 5!
  3. 12! + 5!
  4. 512
  1. 27, 125, 343, 729, 1331,?
  1. 2197
  2. 1864
  3. 2469
  4. 1965
  1. If 3888 is divided by the square of a number and the answer so obtained is multiplied by 21, then the final answer is 252. What is the number?
  1. 17
  2. 19
  3. 18
  4. 16
  1. A pipe can fill a tank in 32 h. After 8 h, 7 more similar pipes are used. What is the additional time required to fill the tank?
  1. 3 h
  2. 2 h
  3. 5 h
  4. 4 h
  1. Find the number, if 4/5 of that number exceeds its 2/3 by 4.
  1. 15
  2. 27
  3. 30
  4. 45

Solution:

  1. Answer: (D)

HCF is always a factor of LCM. None of the given options is a multiple of 18. Therefore, the correct option is “None of these”.

  1. Answer: (B)

Since HCF is a factor of both numbers, these numbers must be 12a and 12b, where a and b are relatively prime. According to the given condition, 12ab = 924. Therefore, ab = 77 So, the required possible pairs are (12, 924) and (84, 132).

  1. Answer: (B)

Let the usual speed be x km/h.

∴ Usual time = 60/x h

New time = 60/(x+3) h

∴60/x -60/(x + 3) = 1

x2 + 3x – 180 = 0

x = 12 or –15 Disregarding the negative value, the usual speed of Ajay is 12 km/h.

  1. Answer: (B)

Let the first part be x, then the second part is 12 – x. According to the question, 3x + 4(12 – x) = 43

3x + 48 – 4x = 43

– x = 43 – 48

– x = – 5

x = 5

First number = 5

Second number = 12 – 5 = 7 Difference = 7 – 5 = 2

  1. Answer: (D)

(x – 5) (x – 13) = x2 – 18x + 65

For a quadratic equation, ax2 + bx + c = 0, the minimum value of the equation is calculated as             (4ac- b2)/4a . Therefore, for the quadratic equation, x2 – 18x +65 = 0, the minimum value will be

4(1)(65) -(-18)2/ 4(1)

(260-324)/ 4 =-64/4=-16

  1. Answer: (D)

Since each question can be answered in 5 ways. Therefore total number of the possible sequence = 512

  1. Answer: (A)

The terms of the given series are 33, 53, 73, 93 and 113. By following the same pattern, the required term is 133 = 2197

  1. Answer: (C)

Let the required number be x. According to the question, 3888 ÷ x2 = a and a × 21 = 252 On solving, we get a = 12 and x2 = 324 Hence, the required number is 18.

  1. Answer: (A)

The pipe can fill 1/32 of the tank in 1 h. After 8 h, remaining part = 3/4

Remaining time = (3/4)/(8×1/32) = 3 h

  1. Answer: (C)

Let the required number be x. So, according to the question,  4/5 x – 2/3x =4

Therefore x = 30

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