RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-18)

Dear Aspirants, Here we have given the Important RRB ALP & Technicians Exam 2018 Practice Test Papers. Candidates those who are preparing for RRB ALP 2018 can practice these Arithmetic Questions to get more confidence to Crack RRB 2018 Examination.

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1. If a = 115, b = -113, c = –2, then what is the value of a³ + b³ + c³?

1. 69000
2. 12995
3. 38985
4. 77970

2. 500 ÷ 50 × 5 =?

1. 2
2. 5
3. 50
4. 10

3. X is twice as efficient as Y. X takes 20 days to complete a job. In how many days, can X and Y complete the job together?

1. 30
2. 25
3. 40
4. 40

4. The difference between a number and its two-third is 24. Find the number.

1. 48
2. 36
3. 60
4. 72

5. 10000 ÷ 100 ÷ 10 =?

1. 1
2. 10
3. 100
4. 1000

6. What will be the compound interest accrued on a sum of Rs. 7,200 at a rate of 5% per annum in 2y?

1. Rs. 738
2. Rs. 1,738
3. Rs. 1,268
4. Rs. 648

7. Population of a country increases every year by 10%. If the population in January 2006 was 15.8 lakh, what was the population in January 2008?

1. 19,11,800
2. 18,96,000
3. 19,11,600
4. 18,94,000

8. John travelled 240 km at a certain speed and then another 192 km at 8 km/h faster. If the entire trip was of 10 h, find his initial speed.

1. 45 km/h
2. 60 km/h
3. 40 km/h
4. 75 km/h

9. The ratio of present ages between Jyoti and Ankita is 7: 5. If after six years, their ages will be in the ratio of 4: 3, what would be the present age of Ankita?

1. 32
2. 36
3. 30
4. 35

10. Fraction becomes 4 when 1 is added to the numerator and becomes 5 when 1 is subtracted from the denominator. The numerator of the given fraction is

1. 15
2. 11
3. 13
4. 17

Solution:

1. Answer: (d)

Note that here, a + b + c = 0 Therefore, a³ + b³ + c³ = 3abc = 3 (115) (-113) (-2) = 77970.

2.Answer: (c)

According to the BODMAS rule, ? = 500 ÷ 50 × 5 = 10 × 5 = 50

3. Answer: (d)

X’s one-day work = 1/20

Y’s one-day work = 1/40 (because X is twice as efficient as Y) X and Y’s one-day work 1/20+1/ 40=3/40

4.Answer: (d)

Let the required number be x. According to the question,

x – 2x/3 = x/3 = 24

Therefore, x = 72

5. Answer: (b)

If the expression includes more than one similar operation, solve from the left hand side first, and then the other. Therefore, ? = 10000 ÷ 100 ÷ 10 = 100 ÷ 10 = 10

6. Answer: (a)

C.I. for 1st year = 5% of 7200 = ` 360

C.I. for 2nd year = 5% of 7200 + 5% of 360 = 360 + 18 = ` 378

C.I. for 2 years = 360 + 378 = ` 738

7. Answer: (a)

Population in 2006 = 15,80,000

Rate of growth = 10%

Population in 2008 = 158000(1+10/100)² = 1580000 × 1.1 × 1.1 = 19,11,800

8. Answer: (c)

Let the initial speed of John be x km/h

∴ According to the question, 240/x+ 192/( x+ 8)

240(x + 8) + 192x = 10(x² + 8x)

10x² – 352x –1920 = 0

x = 40, –24/5

By ignoring the negative value, the required speed of John = 40 km/h.

9. Answer: (c)

Let Jyoti’s present age be 7x years and Ankita’s present age be 5x years.

Then, after 6 years, their ages will be:(7x+6) /(5x+6)=4/3

3(7x+6) = 4(5x+6)

21x+18 = 20x+24

x = 6

Therefore, Ankita’s present age = 5×6 = 30 years.

10. Answer: (a)

Let the fraction be x/y

(X+1)/y=4

=>x-4y+1=0——->(1)

x/(y-1)=5

=>x-5y+5=0——–>(2)

On solving eqn 1 and 2, x=15, y=4

Numerator=15

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