Dear Aspirants, Here we have given the Important RRB ALP & Technicians Exam 2018 Practice Test Papers. Candidates those who are preparing for RRB ALP 2018 can practice these Arithmetic Questions to get more confidence to Crack RRB 2018 Examination.
[WpProQuiz 1454]
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(A) 10
(B) 30
(C) 20
(D) 11
(A) 850
(B) 780
(C) 900
(D) 800
(A) Rs. 540
(B) Rs.600
(C) Rs. 590
(D) Rs. 650
(A) 277
(B) 291
(C) 349
(D) 554
(A) 512
(B) 360
(C) 396
(D) 420
(A) 322
(B) 46
(C) 151
(D) 197
7.If the sum and product of the roots of a quadratic equation are 8 and 15, then the quadratic equation is
(A) x2 – 8x – 15 = 0
(B) x2 + 8x + 15 = 0
(C) x2 – 8x + 15 = 0
(D) x2 + 8x – 15 = 0
(A) 3: 4
(B) 4: 3
(C) 9: 16
(D) √3: √4
8, 12, 30, 105, 472.5, ? , 16891.875
(A) 2598.75
(B) 2597.25
(C) 2598.25
(D) 2545.25
(A) 4
(B) 6
(C) 5
(D) 7
Answer:
The given expression is: ab = 361
ab = 192
Comparing both sides, we get a = 19 & b = 2
Value of (a+1)b-1=( 19+1)2-1= (20)1= 20.
Marks obtained by a student = (64% – 9%) of maximum aggregate marks = 55% of the maximum aggregate marks
55% of aggregate marks = 440
Aggregate marks = 440/55*100= 800
Discount = 10% (Given)
Therefore, S.P. = 90% of M.P ….(1)
Profit = 20% (Given)
Therefore, S.P. = 120% of C.P…..(2)
By combining (1) and (2), we get:
90% of M.P. = 120% of C.P.
M.P. = 4/3 of C.P. = 4/3 × 450 = 600
Let the first number be x Second number = 23 – x
According to the question, x – (23 – x) = 5 x – 23 + x = 5 2x = 28 x = 14
First number = 14
Second number = 9
Sum of the squares of numbers = 142 + 92 = 196 + 81 = 277
There are 4 vowels and 5 consonants in the word ALLAHABAD.
Let’s consider 4 vowels to be 1 letter.
Now, we have 5 + 1 = 6 letters, and these 6 letters can be arranged in 6!/2! = 360 ways. (Note that the consonant L is there twice in the word.)
Also, the 4 vowels can be arranged among themselves in 4!/4! ways.
Therefore, the total number of words that can be formed is 360 × 1 = 360.
Since the numbers are in the ratio 2: 7 and HCF is 23, the required LCM = 2 × 7 × 23 = 322
7.Answer: C
Equation with roots α and β is x2 – (α + β) x + αβ = 0. Hence, the required equation is x2 – 8x + 15 = 0.
Let the radius be r and height of the cylinder is h.
4/3 πr3= πr2h
4/3 r=h
h/r =4/3
472.5 × 5.5 = 2598.75
A number is divisible by 11 if the difference between the sum of numbers at even places and the sum of numbers at odd places is either 0 or divisible by 11.
The difference of the sum of numbers at even places and odd places = 2 + 5 + 7 + 3 – (3 + 6 + x + 2)
= 17 – 11 – x
= 6 – x
6 – x is zero, when x = 6
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-1)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-2)
This post was last modified on March 8, 2018 7:09 pm