Dear Aspirants, Here we have given the Important RRB ALP & Technicians Exam 2018 Practice Test Papers. Candidates those who are preparing for RRB ALP 2018 can practice these Arithmetic Questions to get more confidence to Crack RRB 2018 Examination.
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(A) 432/1586
(B) 432/793
(C) 864/793
(D) 0.5
(1) 12.00 pm
(2) 12.00 am
(3) 11.30 pm
(4) 12.30 am
(A) 102.606
(B) 167.203
(C) 269.269
(D) 102.066
(A) 7440
(B) 1240
(C) 2480
(D) 3720
(A) 1310
(B) 1804
(C) 1540
(D) 1236
(A) Rs. 2,940
(B) Rs. 3,240
(C) Rs. 3,480
(D) Rs. 3,624
(A) 50 years
(B) 46 years
(C) 44 years
(D) 52 years
(A) isosceles
(B) equilateral
(C) scalene
(D) right angled
(A) 6: 1
(B) 1: 6
(C) 7: 2
(D) 9: 2
(A) 2
(B) 8
(C) 6
(D) 3
Solutions
(3.5×3.5 -1.9×1.9)/(3.5×3.5+1.9×1.9)= (3.52-1.92)/(3.52+1.92)= (12.25-3.61)/(12.25+3.61)= 864/1586= 864/1586 = 432/793
Distance travelled by first train before second started is 54 × 2 = 108 km. Time taken by second to overtake first train will be 108/(72-54)=108/18 = 6 hours
Second train will catch the first train at 6 pm + 6 hours = 12 am.
The sum of squares of n natural numbers is n(n+1)(2n+1)/6 . So, for n = 15, sum will be, 15(15+1)(2*15+1)/6=1240
Number of the triangles which can be formed by joining 21 points in a plane = 21C3
But out of these 21 points, 6 points are collinear.
Number of possible triangles = 21C3-6C3 =21*20*19/(3*2*1) – 6*5*4/(3*2*1)
= 1330 – 20 = 1310
Let k be the interest for the first year and the rate of interest is r% per annum.
Now k(1+r/100) -k= 360
kr/100=360
If rate of interest becomes 3 times then Interest for the 1st year = 3k
The difference between the compound interest for the second year and the first year = 3k(1+3r/100) -3k
=9kr/100
Putting the value of kr/100 we get 9 kr/100 = 9 × 360 = Rs. 3,240
Let the present age of person be x year. According to the question,
5(x + 5) – 5(x – 5) = x
5x + 25 – 5x + 25 = x
x = 50 Therefore, the age of the person 6 years ago = x – 6 = 44 years
The sum of all the angles of a triangle is 180.
4x+6(x – 5) + (x2+15)/4 = 180
x2 + 40x – 825 = 0
x = 15 So, the angles are 60o, 60o and 60o, and therefore the triangle is equilateral.
Let the radii and heights of the cone A are ra and ha, and that of cone B are rb and hb, respectively.
Ratio of volumes of cone A and B is 1/3πra2ha/1/3πrb2hb = ra2/rb2 (ha/hb) = 1/2
= 1/9(ha/hb) =1/2
ha/hb =9/2
Let a/7=b/8=c/9=x
a = 7x, b = 8x and c = 9x
(a+b+c)/b= (7x+8x+9x)/8x =24x/8x =3
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-1)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-2)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-3)
This post was last modified on March 10, 2018 11:32 am