Dear Aspirants, Here we have given the Important RRB ALP & Technicians Exam 2018 Practice Test Papers. Candidates those who are preparing for RRB ALP 2018 can practice these Arithmetic Questions to get more confidence to Crack RRB 2018 Examination.
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- Simplification
3/7 of 14/5÷21/15 of x = 12
- 10
- 12
- 14
- 20
- If the profit on selling a book for Rs.160 is the same as the loss on selling it for Rs.140, then the cost price of the book is
- 125
- 175
- 100
- 150
- The ratio income of Raju and Babu is 5 : 4. Difference between their incomes is 2000. What is the income of Babu?
- 10000
- 8000
- 18000
- 4000
- Sum of Ages of Ram and sita is 40. Ratio of Ram and Ravi’s age is 5: 4. Find the age of Sita?
- 35
- 30
- 25
- can’t be determined
- There are 50 boys in a hostel has a provision for 30 days. After 10 days 10 more boys join with them. In how long lasts the provision?
- 16 days
- 15 days
- 16 ½ days
- 16 2/3 days
6. A can do 2/3rd work in 6 days. B can do ½ works in 9 days. If they do together the work how long the work will be finish?
- 3 days
- 6 days
- 12 days
- 15 days
- √x +1/√x = 4. Find x2+1/x2= ?
- 190
- 192
- 194
- 196
- Find the value of x
tan 30°. cot 30°+ sin 30°. Cos 60° – cosec 90°
- 1
- 0
- 1/2
- 1/ 4
- Area of triangle is 132cm. Find the base if the height of the triangle is 11?
- 24
- 12
- 48
- 16
- Find the next term
4, 4, 6, 12, 30, 90, x
- 390
- 315
- 340
- 320
Answers :
1). Answer: C
3/7× 14/5×15/21× x = 12
6/7x =12
X = 12 × 7/6 = 14
2). Answer: d
Cost price of the book = x
Profit = 160 – x
Loss s= x- 140
2x = 160 + 140 = 300/ 2 = 150
3). Answer: B
5x – 4x = 2000
X = 2000
Babu’s salary = 2000*4 = 8000
4). Answer:
Total age of ram and sita = 40
Ram: Ravi = 5 : 4
There is no common data to conclude answer.
5). Answer: D
(50×20)/ 60 = 50 / 3 = 16 2/ 3
6). Answer: B
2/3 work in 6 days —————– whole work done by A in 9 days
B = 1/ 18 days
A + B = 1/ 9 + 1/ 18 = 3 / 18 = 1/ 6
A and B can complete the job in 6 days
7). Answer: C
√x +1/√x = 4
Take square both sides
(√x)2 + (1/√x)2 = (4)2
(X + y)2 = x2 + y2+2xy
X+1/x+2.x.1/x = 16
X+1/x = 16-2 = 14
(X+1/x)2 = (14)2
Repeating same formula
X2 + 1/x2 = 196 – 2 = 194
8). Answer: D
Tan 30° .cot 30° + sin 30° . cos 60° – cosec 90°
1/√3 .√3 + 1/2. 1/2 – 1 = 1+ 1/4 − 1 = ¼
9). Answer: A
Area of Triangle = ½ × base ×Height
132 = 1/2 × base × 11
Base = (132 ×2)/11 = 12×2 = 24
10). Answer: B
4×1 4×1.5 6×2 12×2.5 30×3 90×3.5 315
RRB ALP 2018 – “All in One” Study Materials and Practice Sets
