Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for IBPS RRB Clerk Mains 2021Â so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
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Pie chart
Directions (1-5): Study the following information carefully and answer the questions given below.
The given pie chart shows the percentage of total employees (who like both tea and coffee) in six different companies.
The given table shows the percentage of the employees who like coffee in six different companies.
1) If four-fifth and three-fourth of the employees in S and U are male and the ratio of the number of male who like coffee to tea in S and U is 5:4 and 2:3 respectively, then what is the difference between the number of female employees who like tea in S and U together and the number of female employees who like coffee in S and U?
A.28
B.32
C.36
D.40
E.42
2) What is the ratio of the number of employees who like tea in P and R together to S and T together?
A.121:133
B.127:134
C.131:142
D.133:145
E.None of these
3) What is the approximate average number of employees who like coffee in all the companies together?
A.268
B.272
C.278
D.260
E.256
4) Average number of employees who like tea in all the companies together is what percent of the total number of employees in P, S and R together?
A.19.98%
B.21.46%
C.23.34%
D.17.78%
E.25.61%
5) If one-fourth of the employees in P like Apple juice and 15% of the employees in Q are like Apple juice, one-fifth of the employees in R are like apple juice and three-twenty employees in S are like Apple juice, then find the total number of employees in P, Q, R and S who like apple juice?
A.454
B.456
C.444
D.464
E.465
Quadratic equation
Directions (06-10): Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,
6) I) x2 – 44x + 468 =0
II) y2– 39y + 378=0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
7) I)Â x2Â + 27x + 162=0
II)2y2+ 42y + 216=0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
8) I) 3x2 – 51x + 216=0
II)Â y2+ 19y – 66 =0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
9) I) x2 – 10x – 504 =0
II)Â y2+ 40y + 396 =0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
10) I)Â x2Â + 275 = 396
II) y2– 23y + 132 =0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
Answers :
Directions (1-5) :
1) Answer: C
Number of male employees in S = 4/5 * 720 = 576
Number of male employees in U = 3/4 * 880 = 660
Number of male employees who like coffee in S = 5/9 * 576 = 320
Number of male employees who like tea in S = 4/9 * 576 = 256
Number of male employees who like coffee in U = 660 * 2/5 = 264
Number of male employees who like tea in U = 660 * 3/5 = 396
Number of female employees like tea in S = 324 – 256 = 68
Number of female employees like coffee in S = 396 – 320 = 76
Number of female employees like coffee in U = 352 – 264 = 88
Number of female employees like tea in U = 528 – 396 = 132
Difference = (132 + 68) – (76 + 88)
= 200 – 164
= 36
2) Answer: E
Required ratio = (390 + 360):(324 + 480)
= 750:804
= 125:134
3) Answer: B
Required average = (352 + 130 + 352 + 240 + 396 + 160)/6
= 1630/6
= 272
4) Answer: B
Required percentage = ((390 + 288 + 360 + 324 + 480 + 528)/6)/(520 + 600 + 720) * 100
=395*100/1840
= 21.46%
5) Answer: A
Number of employees like Apple juice in P =1/4 * 520 = 130
Number of employees like Apple juice in Q = 15/100 * 640 = 96
Number of employees like Apple juice in R = 1/5 * 600 = 120
Number of employees like Apple juice in S = 720 * 3/20 = 108
Required total = 130 + 96 + 120 + 108 = 454
6) Answer: C
x2 – 44x + 468 = 0
x2 – 26x – 18x + 468 = 0
x(x – 26) – 18(x – 26) = 0
(x – 18)(x – 26) = 0
x = 18, 26
y2 – 39y + 378 = 0
y2 – 21y – 18y + 378 = 0
y(y – 21) – 18(y – 21) = 0
(y – 18)(x – 21) = 0
y = 18, 21
Relationship between x and y cannot be established.
7) Answer: C
x2Â + 27x + 162 = 0
x2Â + 9x + 18x + 162 = 0
x(x + 9) + 18(x + 9) = 0
(x + 18)(x + 9) = 0
x = -18, -9
2y2Â + 42y + 216 = 0
2y2Â + 24y + 18y + 216 = 0
2y(y + 12) + 18(y + 12) = 0
(2y + 18)(y + 12) = 0
y = -9, -12
Relationship between x and y cannot be established.
8) Answer: A
3x2 – 51x + 216 = 0
3x2 – 24x – 27x + 216 = 0
3x(x – 8) – 27(x – 8) = 0
(3x – 27)(x – 8) = 0
x = 9, 8
y2Â + 19y – 66 = 0
y2Â + 22y – 3y – 66 = 0
y(y + 22) – 3(y + 22) = 0
(y – 3)(y + 22) = 0
y = 3, -22
x > y
9) Answer: B
x2 – 10x – 504 = 0
x2 – 28x + 18x – 504 = 0
x(x – 28) + 18(x – 28) = 0
(x + 18)(x – 28) = 0
x = -18, 28
y2Â + 40y + 396 = 0
y2Â + 18y + 22y + 396 = 0
y(y + 18) + 22(y + 18) = 0
(y + 22) (y + 18) = 0
y = -22, -18
x ≥ y
10) Answer: E
x2Â + 275 = 396
x2Â = 121
x = 11, -11
y2 – 23y + 132 = 0
y2 – 12y – 11y + 132 = 0
y(y – 12) – 11(y – 12) = 0
(y – 11)(y – 12) = 0
y = 11, 12
x ≤ y
