Dear Readers, Important Practice Aptitude Questions with solution for Upcoming SBI Clerk Exam, candidates those who are preparing for those exams can use this practice questions.
Direction (01 to 10): what will come in the place of the questions mark (?) in the following questions?
1).2×(4/6) + 3×(6/7)+ 4×(5/7)+ 3×(2/3) = ?
a) 13×(3/7)
b) 14×(19/21)
c) 15×(19/21)
d) 14×(9/21)
e) None of these
2).22% of 365 – 36% of 465 = ?
a) 87
b) 87.1
c) -87.1
d) -77.1
e) None of these
3).?% of 460 – 34% of 356 = 456
a) 110.5
b) 123.4
c) 120.4
d) 125.4
e) None of these
4).82% of 285 + ?% of 456 = 845
a) 134.06
b) 135.06
c) 125.06
d) 124.06
e) None of these
5).√(729×81) + (19)2+ 11 = ?
a) 651
b) 615
c) 515
d) 551
e) None of these
6).(0.027)2÷ (0.09)5× (0.0081) = (0.3)?+4
a) 3
b) 4
c) -4
d) -3
e) None of these
7).(2.25)2 ÷ (3.375)4× (1.5)5 = (1.5)?-7
a) -3
b) -4
c) 3
d) 4
e) None of these
8).(√125.44×85÷8) – 11 = (?)2 ÷ 3
a) 12
b) 16
c) 28
d) 17
e) 18
9).67% of √676 ÷ 0.01 = ? + 577
a) 1165
b) 1156
c) 1651
d) 1166
e) None of these
10).√(122 × 24 ÷ 5 – 63 + 149.8) = (?)2
a) 25
b) 5
c) 625
d) 15
e) 17
Answers:
1).b) 2).c) 3).d) 4).a) 5).b) 6).c) 7).d) 8).e) 9).a) 10).b)
Detailed Solutions:
1).? = 2×(4/6)+ 3×(6/7)+ 4×(5/7)+ 3×(2/3)
= 8/3 + 27/7+33/7+11/3
=(56+81+99+77)/21
= 313/21
= 14×(19/21)
2).?= [(365×22)/100] – [(465×36)/100]
= 80.30 – 167.40 = – 87.1
3).(460×?)/100 – (356×34)/100 = 456
à460 × ? – 12104= 45600
à460 × ? = 45600 + 12104
= 57704
?= 57704 / 460= 125.4
4).(285×82)/100 + (456×?)/100 = 845
à23370 + 456 × ? = 84500
à456 × ?= 84500 – 23370
= 61130
à? = 61130/456 = 134.06
5).√(729×81) + (19)2 + 11 = ?
à? = 243 + 361 + 11 = 615
6).(0.027)2 ÷ (0.09)5 × (0.0081)=(0.3)?+4
à[(0.3)3]2 ÷ [(0.3)2]5× (0.3)4
= (0.3)?+4
à(0.3)6-10+4= (0.3)?+4
à? + 4 = 0
à? = -4
7).(2.25)2÷ (3.375)4×(1.5)5= (1.5)?-7
à[(1.5)2]2 ÷ [(1.5)3]4 × (1.5)5
= (1.5)?-7
à(1.5)4 ÷ (1.5)12 × (1.5)5
= (1.5)?-7
à(1.5)4-12+5 = (1.5)?-7
à-3 = ? – 7
à?= 7-3=4
8).(√125.44 × 85÷8) -11 = (?)2/3
à[(11.2×85)/8]-11= (?)2/3
à119 -11 =(?)2/3
à108 × 3 = (?)2
à? = √324 = 18
9).√676 × (67/100) ÷ (1/100) = ? + 577
à26×(67/100) ×100=?+577
à1742 = ? + 577
à? = 1742 – 577 = 1165
10).(?)2= √(691.2 – 216 + 149.8)
= √ 625 = 25
à? = √25 =5
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