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Missing Number Series
Direction (1 – 5): What will come in place of question mark (?) in the following number series?
1) 12, 84, 432, ? , 5232, 10476
a) 1740
b) 1830
c) 2240
d) 2680
e) 3240
2) 23, 31, ?, 81, 131, 203
a) 48
b) 49
c) 42
d) 39
e) 43
3) 32, 176, ?, 5324, 29282, 161051
a) 968
b) 1240
c) 876
d) 764
e) 1459
4) 120, 649, 1010, 1299, 1468, 1589, ?
a) 1670
b) 1638
c) 1656
d) 1640
e) 1672
5) 992, 1056, 1122, 1190, ?, 1332
a) 1260
b) 1240
c) 1220
d) 1280
e) 1250
Caselet
Directions (6 – 10): Study the following information carefully and answer the question given below?
Amit can do a piece of work in 60 days. With the help of Rahul, he can complete the work in 180/7 days. Bhagat can do the same work in 15 days less than that of Rahul, when working alone. Amit started the work, Rahul and Bhagat join him every third day and thus time taken by them to complete the work is — (A) —days. Efficiency of Seema is half of the efficiency of Rahul. Amit and Bhagat started the work. Seema joined them after five days. Time taken by them to complete the remaining part of the work is —- (B) —– days. Seema started the work and left after 10 days. Reeta complete the remaining part of the work in 80/3 days. Amit and Reeta together can complete the work in —- (C) —– days. Garima and Rahul together can complete half of the work in 90/13 days. Garima and Reeta started the work and left after five days. Bhagat can complete the remaining part of the work in —– (D) —– days. If Reeta, Seema, Amit and Bhagat started the work together, they can complete the work in — (E) —days.
6) Find the place value of (A)?
a) 53(1/11)
b) 59(3/13)
c) 47(7/17)
d) 49(1/6)
e) None of these
7) Find the place value of (B)?
a) 23/2
b) 135/11
c) 133/10
d) 44/3
e) None of these
8) Find the place value of (C)?
a) 15
b) 18
c) 20
d) 25
e) None of these
9) Find the place value of (D)?
a) 35/2
b) 25/3
c) 18
d) 21/2
e) None of these
10) Find the place value of (E)?
a) 140/11
b) 180/17
c) 160/19
d) 150/13
e) None of these
Answers :
Directions (1-5) :
1) Answer: A
12 * 6 + 12 = 84
84 * 5 + 12 = 432
432 * 4 + 12 = 1740
1740 * 3 + 12 = 5232
5232 * 2 + 12 = 10476
2) Answer: B
23 + 22 * 2 = 31
31 + 32 * 2 = 49
49 + 42 * 2 = 81
81 + 52 * 2 = 131
131 + 62 * 2 = 203
3) Answer: A
32 * 5.5 = 176
176 * 5.5 = 968
968 * 5.5 = 5324
5324 * 5.5 = 29282
29282 * 5.5 = 161051
4) Answer: B
120 + 232 = 649
649 + 192 = 1010
1010 + 172 = 1299
1299 + 132 = 1468
1468 + 112 = 1589
1589 + 72 = 1638
5) Answer: A
31 * 32 = 992
32 * 33 = 1056
33 * 34 = 1122
34 * 35 = 1190
35 * 36 = 1260
36 * 37 = 1332
Directions (6-10) :
6) Answer: B
1/Amit = 1/60
1/Amit + 1/Rahul = 7/180
=> 1/60 + 1/Rahul = 7/180
=> 1/Rahul = 7/180 – 1/60
=> 1/Rahul = (7 – 3)/180
=> 1/Rahul = 4/180
=>1/Rahul = 1/45
1/Bhagat = 1/(45 – 15)
=>1/Bhagat = 1/30
3 days’ work = 1/60 + 1/60 + (1/60 + 1/45 + 1/30)
=>3 days’ work = (3 + 3 + 3 + 4 + 6)/180
=>3 days’ work = 19/180
=> 3 x 9 = 57 days’ work = 19/180 x 9 = 171/180
Remaining work = 1 – 171/180
= (180 – 171)/180
= 9/180
= 1/20
58 day’s work = 1/60
59 day’s work = 1/60
Remaining part of the work = 1 – 171/180 – 1/60 – 1/60
= (180 – 171 – 3 – 3)/180
= (180 – 177)/180
= 3/180
= 1/60
Let time taken by them to complete remaining part of the work = n
n x (1/60 + 1/45 + 1/30) = 1/60
=> n x (3 + 4 + 6)/180 = 1/60
=> n = 1/60 x 180/13
=> n = 3/13
Required time = 59 + 3/13 = 59 3/13
Place value of (A) = 59 (3/13)
7) Answer: B
1/Seema = ½ x 1/45
=>1/Seema = 1/90
Let time taken by them to complete remaining part of the work = n
5/60 + 5/30 + n x (1/60 + 1/30 + 1/90) = 1
=> 1/12 + 1/6 + n x (3 + 6 + 2)/180 = 1
=> 11n/180 = 1 – 1/12 – 1/6
=> 11n/180 = (12 – 1 – 2)/12
=> n = 9/12 x 180/11
=> n = 135/11
Place value of (B) = 135/11
8) Answer: C
Let, Reeta alone can complete the work in n days.
10/90 + 80/3n = 1
=> 1/9 + 80/3n = 1
=> 80/3n = 1 – 1/9
=> 80/3n = (9 – 1)/9
=> n = 80/3 x 9/8
=> n = 30
1/Reeta = 1/30
Let, Amit and Reeta together can complete the work in t days.
t x (1/60 + 1/30) = 1
=> t x (1 + 2)/60 = 1
=> t = 60/3
=> t = 20 days.
Place value of (C) = 20
9) Answer: A
1/Garima + 1/Rahul = 13/90 x 1/2
=>1/Garima + 1/45 = 13/180
=> 1/Garima = 13/180 – 1/45
=> 1/Garima = (13 – 4)/180
=> 1/Garima = 9/180
=>1/Garima = 1/20
Let, required number of days = n
5/20 + 5/30 + n/30 = 1
=> ¼ + 1/6 + n/30 = 1
=> n/30 = 1 – ¼ – 1/6
=> n/30 = (12 – 3 – 2)/12
=> n = 30 x 7/12
=> n = 35/2 days
Place value of (D) = 35/2
10) Answer: B
Let, required number of days = n
n x (1/30 + 1/90 + 1/60 + 1/30) = 1
=> n x (6 + 2 + 3 + 6)/180 = 1
=> n = 180/17 days
Place value of (E) = 180/17
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