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Wrong number series
Direction (1 – 5): Find the wrong term in the following number series?
1) 21, 10, 11, 16.5, 32, 77.5, 235.5
a) 10
b) 38
c) 97.5
d) 295.5
e) 5
2) 57, 85, 91, 121, 90
a) 91
b) 121
c) 90
d) 85
e) None of these
3) 6562, 6243, 5932, 5629, 5330, 5047
a) 5629
b) 5330
c) 5047
d) 6243
e) None of these
4) 110, 510, 834, 1090, 1285, 1430
a) 1285
b) 1430
c) 1090
d) 834
e) None of these
5) 2520, 630, 180, 60, 24, 10
a) 10
b) 24
c) 180
d) 630
e) None of these
Data Interpretation
Direction (6 – 10): Study the following information carefully and answer the given questions?
The given line graph shows the length of four different trains – A, B, C and D.
6) Ratio of the length of train A to E is 4: 3 and train A cross a platform in 21 seconds. Train E can cross the same platform in 13.5 seconds. Ratio of the speed of train A to train E is 3: 4, then how much time both train will cross each other if both trains are running in opposite direction?
a) 12 seconds
b) 9 seconds
c) 18 seconds
d) 15 seconds
e) None of these
7) If the ratio of the speed of train B and E is 3: 2 and the time taken to cross a man standing in a platform in the ratio of 1: 2, what is the length of train E?
a) 300 m
b) 400 m
c) 200 m
d) Cannot be determine
e) None of these
8) Train D crosses an electric pole and the platform in 18 seconds and 54 seconds respectively. What is the difference between the time taken by train D crosses train C running opposite direction at the speed of 50 kmph and time taken by train C cross the same platform?
a) 18.8 seconds
b) 21.6 seconds
c) 19.5 seconds
d) 24.8 seconds
e) None of these
9) A train E over takes two cars they are moving in the same direction in which the train E is going at the speed of 4 kmph and 8 kmph respectively and crosses them in 12 seconds and 15 seconds respectively. What is the ratio of the length of train E to train B?
a) 1:7
b) 2:9
c) 3:11
d) 4:13
e) Cannot be determine
10) Train A crosses train B running in same direction in 36 seconds. If the ratio of the speed of train A to B is 4:9 and also train A crosses the tunnel in 45 seconds.
From the statement given in the above question which of the following can be determined.
a) Length of Tunnel
b) Speed of train A
c) Time taken by train A crosses the pole
d) Time taken by train B crosses the Tunnel
a) All A, B, C and D
b) Only B and C
c) Only D and B
d) Only A, B and C
e) Only A, B and D
Answers :
Directions (1-5) :
1) Answer: E
21 * 0.5 – 0.5 = 10
10 * 1 + 1 = 11
11 * 1.5 – 1.5 = 15
15 * 2 + 2 = 32
32 * 2.5 – 2.5 = 77.5
77.5 * 3 + 3 = 235.5
2) Answer: C
19 * 3 = 57
17 * 5 = 85
13 * 7 = 91
11 * 11 = 121
7 * 13 = 91
3) Answer: B
81*81 + 1 = 6562
79*79 + 2 = 6243
77*77 + 3 = 5932
75*75 + 4 = 5629
73*73+5 = 5334
71*71 + 6 = 5047
4) Answer: A
110 + (20*20) = 510
510 + (18*18) = 834
834 + (16*16) = 1090
1090 + (14*14) = 1286
1286 + (12*12) = 1430
5) Answer: A
2520/4 = 630
630/3.5 = 180
180/3 = 60
60/2.5 = 24
24/2 = 12
Directions (6-10) :
6) Answer: B
Length of train A = 200 m
Length of train E = 3/4 * 200 = 150 m
Speed of train A = 3x
Speed of train B = 4x
Length of the platform = y
200 + y = 3x * 5/18 * 21
400 + 2y = 35x
35x – 2y = 400 ——- (1)
150 + y = 4x * 5/18 * 13.5
150 + y = 15x
15x – y = 150 —- (2)
(1) – (2) * 2
5x = 100
x = 20
Speed of train A = 3 * 20 = 60 kmph
Speed of train B = 4 * 20 = 80 kmph
Required time = (150 + 200)/(140 * 5/18) = 9 seconds
7) Answer: B
Length of train B = 300 m
Length of train E = e
Speed of train B = 3x
Speed of train E = 2x
Time taken by train B cross a man = y
Time taken by train E cross a man = 2y
300 = 3x * 5/18 * y
360 = xy ——– (1)
e = 2x * 5/18 * 2y
9e = 10xy —— (2)
(1) in (2)
9e = 10 * 360
e = 400 m
8) Answer: B
Length of train D = 150 m
Length of train C = 250 m
Length of the platform = y
Speed of train D = x
Speed of train C = 50 kmph
150 = x * 5/18 * 18
150 = 5x
x = 30 kmph
150 + y = 30 * 5/18 * 54
y = 300 m
Time taken by train D crosses train C = 400/(80 * 5/18)
= 18 seconds
Time taken by train C crosses the platform = (550)/(50 * 5/18)
= 39.6 seconds
Difference = 39.6 – 18 = 21.6 second
9) Answer: B
Length of train E = e
Speed of train E = x
(x – 4) * 12 = (x – 8) * 15
12x – 48 = 15x – 120
3x = 72
x = 24 kmph
Length of train E = (24 – 4) * 5/18 * 12
= 1200/18
= 200/3
Required ratio = 200/3 : 300
= 2: 9
10) Answer: A
Length of train A = 200 m
Length of train B = 300 m
Speed of train A = 4x
Speed of train B = 9x
500 = (5x) * 5/18 * 36
x = 10 km
Speed of train A = 4 * 10 = 40 kmph
Speed of train B = 9 * 10 = 90 kmph
Length of the tunnel = y
200 + y = 40 * 5/18 * 45
y = 300 m
Time taken by train A crosses a pole = 200 / (40 * 5/18)
= 18 seconds
Time taken by train B crosses a tunnel = (600)/(90 * 5/18)
= 24 seconds
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