Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for SBI Clerk Mains 2020 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
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Data Interpretation
Directions (1 – 5): Study the following information carefully and answer the questions given below.
The bar chart given below shows the percentage of quantity of wine, soda and water in tank A, tank B, tank C and tank D and line chart given below shown the capacity of the tank A, tank B, tank C and tank D. Study the data carefully and answer the following questions. (Note- all the tanks are filled to its full capacity)
1) If 20% of the quantity of tank A and 30% of the quantity of tank B are mixed in tank E. Find the amount of water in tank E.
A) 34.4 litres
B) 32.4 litres
C) 31.4 litres
D) 31.6 litres
E) 30.4 litres
2) If any three tanks are mixed in a large tank then the maximum quantity of wine can be obtained from which combination?
A) Tank A + Tank B + Tank C
B) Tank A + Tank B + Tank D
C) Tank A + Tank C + Tank D
D) Tank B + Tank C + Tank D
E) Both option c and d are correct.
3) Find the ratio of the quantity of wine, soda and water respectively in a glass if the 40ml liquid is taken from tank C and 60 ml liquid is tank from tank D.
A) 33: 37: 30
B) 30: 37: 33
C) 37: 33: 30
D) 40: 33: 27
E) 33: 47: 20
4) If the price of wine is Rs. 600/litre and price of soda is Rs. 80/litre. Find the amount of profit obtained by selling the whole mixture of tank C at the rate of Rs. 500/litre.
A) Rs. 44000
B) Rs. 54000
C) Rs. 34000
D) Rs. 36000
E) Rs. 64000
5) The total quantity of soda in all the tanks is approximately what percent of the total quantity of wine in all the tanks?
A) 110%
B) 125%
C) 120%
D) 130%
E) 135%
Number Series
Directions (6 – 10): The questions below are based on the given Series-I. The series-I satisfy a certain pattern, follow the same pattern in Series-II and answer the questions given below.
6) I) 4, 20, 60, 300, 900, 4500, 13500
II) 11 …… 2475. If 2475 is nthterm, then what value should come in place of (n + 2)thterm?
A) 34250
B) 18975
C) 12375
D) 37125
E) 25650
7) I) 924, 924, 462, 154, 38.5, 7.7
II) 534 ……. 4.45. If 4.45 is nth term, then what value should come in place of (n – 2)th term?
A) 89
B) 25
C) 72
D) 75
E) 45
8) I) 27, 1357, 2356, 3084, 3595, 3937
II) 55 ….. 4304. If 4304 is nth term, the find the value of n?
A) 7
B) 6
C) 8
D) 9
E) 5
9) I) 57, 66, 39, 84, 21, 102, 3
II) 72 ……. 36. If 36 is nthterm, then what value should come in place of (n+3)rdterm?
A) 117
B) 135
C) 18
D) 92
E) 53
10) I) 12, 24, 96, 576, 4608, 46080
II) 4 …… 184320. If 184320 is nthterm, then find the value of n?
A) 5
B) 6
C) 9
D) 7
E) 8
Answers :
1) Directions (1-5) :
Answer: E
Tank A
20% of 160 = 32 litres
Quantity of water = 50% of 32 = 16 litres
Tank B
30% of 120 = 36 litres
Quantity of water = 40% of 36 = 14.4 litres
Quantity of water in tank E = 16 litres + 14.4 litres = 30.4 litres
2) Answer: C
Quantity of wine
Option a) = 20% of 160 + 25% of 120 + 30% of 180
= 32+ 30+ 54
=116 litres
Option b) 20% of 160 + 25% of 120 + 35% of 150
= 32+30 + 52.5
= 114.5 litres
Option c) 20% of 160+ 30% of 180+ 35% of 150
= 32+ 54+ 52.5
= 138.5 litres (answer)
Option d) = 25% of 120 + 30% of 180+35% of 150
= 30+ 54+ 52.5
= 136.5 litres
3) Answer: A
Tank C
=wine (30% of 40ml) + soda (25% of 40 ml) + water (45% of 40ml)
40ml = wine (12ml) + soda (10ml) + water (18ml)
Tank D
= wine (35% of 60ml) + soda (45% of 60ml) + water (20% of 60ml)
60ml = wine (21ml) + soda (27 ml) + water (12ml)
Glass
Wine (12ml+21ml) + soda (10ml+27ml) + water (18ml+12ml)
Wine (33ml) + soda (37ml) + water (30ml)
Required ratio = 33: 37: 30
4) Answer: B
Selling price of tank C liquid = 180 * 500 = Rs. 90000
Cost price of tank C liquid = cost of wine + cost of soda
Cost price of tank C liquid = quantity of wine * 600 + quantity of soda * 80
Cost price of tank C liquid = (30% of 180) * 600 + (25% of 180) * 80
Cost price of tank C liquid = 54 * 600 + 45 * 80
Cost price of tank C liquid = 32400 + 3600
Cost price of tank C liquid = 36000
Required profit = 90000 – 36000 = Rs. 54000
5) Answer: C
Quantity of soda = 30% of 160 + 35% of 120 + 25% of 180 + 45% of 150
= 48+ 42+45+ 67.5
= 202.5
Quantity of wine = 20% of 160 + 25% 120 + 30% 180+ 35% of 150
= 32 + 30 + 54 + 52.5
= 168.5
Required %age = (202.5/168.5)*100 = 120%
Directions (6-10) :
6) Answer: D
Series I pattern:
4*5 = 20
20*3 = 60
60*5 = 300
300*3 = 900
900*5 = 4500
4500*3 = 13500
Series II pattern:
11*5 = 55
55*3 = 165
165*5 = 825
825*3 = 2475 (nth) term
2475*5 = 12375 (n + 1)th term
12375*3 = 37125 (n + 2)th term
7) Answer: A
Series I pattern:
924 ÷ 1 = 924
924 ÷ 2 = 462
462 ÷ 3 = 154
154 ÷ 4 = 38.5
38.5 ÷ 5 = 7.7
Series II pattern:
534 ÷ 1 = 534
534 ÷ 2 = 267
267 ÷ 3 = 89 (n – 2)th term
89 ÷ 4 = 22.25 (n – 1)th term
22.25 ÷ 5 = 4.45 (nth) term
8) Answer: C
Series I pattern:
27 + (113 – 1) = 1357
1357 + (103 – 1) = 2356
2356 + (93 – 1) = 3084
3084 + (83 – 1) = 3595
3595 + (73 – 1) = 3937
Series II pattern:
55 is first term.
55 + (113 – 1) = 1385
1385 + (103 – 1) = 2384
2384 + (93 – 1) = 3112
3112 + (83 – 1) = 3623
3623 + (73 – 1) = 3965
3965 + (63 – 1) = 4180
4180 + (53 – 1) = 4304
4304 is 8th term.
So, n = 8
9) Answer: B
Series I pattern:
57 + (9*1) = 66
66 – (9*3) = 39
39 + (9*5) = 84
84 – (9*7) = 21
21 + (9*9) = 102
102 – (9*11) = 3
Series II pattern:
72 + (9*1) = 81
81 – (9*3) = 54
54 + (9*5) = 99
99 – (9*7) = 36 (nth term)
36 + (9*9) = 117 (n + 1)th term
117 – (9*11) = 18 (n + 2)th term
18 + (9*13) = 135 (n + 3)rd term
10) Answer: D
Series I pattern:
12*2 = 24
24*4 = 96
96*6 = 576
576*8 = 4608
4608*10 = 46080
Series II pattern:
4 is the first term
4*2 = 8
8*4 = 32
32*6 = 192
192*8 = 1536
1536*10 = 15360
15360*12 = 184320
184320 is 7th term. So, n = 7
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This post was last modified on October 27, 2021 9:55 am