Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for SBI Clerk Mains 2020 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
Wrong number series
Directions (1 – 4): The questions below are based on the given Series – I. The series – I satisfy a certain pattern, follow the same pattern in Series – II and find the wrong number in the series –II.
1) I) 400, 200, 300, 750, 2625
II) 320, 160, 240, 610, 2100
A) 610
B) 240
C) 160
D) 320
E) 2100
2) I) 1180, 1060, 1160, 1080, 1140, 1100
II) 2460, 2340, 2440, 2320, 2420, 2380
A) 2460
B) 2320
C) 2440
D) 2420
E) 2380
3) I) 16, 18, 39, 121, 489, 2451
II) 42, 44, 91, 275, 1113, 5571
A) 42
B) 5571
C) 91
D) 275
E) 1113
4) I) 110, 231, 131, 212, 148, 197
II) 430, 551, 451,530, 468, 517
A) 551
B) 468
C) 530
D) 451
E) 517
Application Sums
5) A, B and C together can do a work in 10 days. B & C together thrice as much as A, A & B together work 4 times as much as C. Who among the following has completed the work earlier?
i) A
ii) C
iii) B
A) Only i
B) Both i and ii
C) Only ii
D) Only iii
E) None of these
6) Initially in a mixture, the ratio of gold and copper is 5:1. ________gm of mixture is drawn and _________gm of copper is added and makes the final mixture with 70 gm gold and 26 gm copper
A) 36, 12
B) 42, 6
C) 72, 12
D) 72, 6
A) Only A
B) Only B
C) Only C
D) Only A and C
E) None of these
7) A and B’s present age ratio is 43:31. If A’s age 8 years ago and B’s age 6 years ago is in the ratio 7:5 respectively. A is _____years old 7 years ago and B is _____years old after 5 years
A) 36, 36
B) 43, 31
C) 50, 36
D) 36, 32
E) None of these
8) P, Q and R started a business by investing in the ratio of 6 : 8 : 13. After 4 months, P invested 25 % more than the initial investment and after another 5 months, P withdraws Rs. 10000 but Q invested Rs. 8000 more than the initial investment. Find the initial investment of Q, if the share of P, Q and R at the end of the year is in the ratio of 51: 68: 104?
A) Rs. 32000
B) Rs. 43000
C) Rs. 38000
D) Rs. 51000
E) None of these
9) Sangeetha invested Rs. 40000 in SI at the rate of 2x % per annum for two years and the same amount is invested in CI at double the rate of simple interest for two years, if she received Rs. 9600 more interest than SI, then find the rate of interest per annum for CI?
A) 15 %
B) 20 %
C) 10 %
D) 24 %
E) None of these
Quadratic Equation
Directions (10): Following questions contain two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,
a) If x > y
b) If x ≥ y
c) If x = y or relationship cannot be determined.
d) If x < y
e) If x ≤ y
10) I) x2 + 19x – 966 = 0
II) y2– 25x + 156 = 0
Answers :
Directions (1-4) :
1) Answer: A
Series I:
400 * 0.5 = 200
200 * 1.5 = 300
300 * 2.5 = 750
750 * 3.5 = 2625
Series II:
320 * 0.5 = 160
160 * 1.5 = 240
240 * 2.5 = 600 (Not 610)
600 * 3.5 = 2100
2) Answer: B
Series I:
1180 – 120 = 1060
1060 + 100 = 1160
1160 – 80 = 1080
1080 + 60 = 1140
1140 – 40 = 1100
Series II:
2460 – 120 = 2340
2340 + 100 = 2440
2440 – 80 = 2360 (Not 2320)
2360 + 60 = 2420
2420 – 40 = 2380
3) Answer: D
Series I:
16 * 1 + 2 = 18
18 * 2 + 3 = 39
39 * 3 + 4 = 121
121 * 4 + 5 = 489
489 * 5 + 6 = 2451
Series II:
42 * 1 + 2 = 44
44 * 2 + 3 = 91
91 * 3 + 4 = 277 (Not 275)
277 * 4 + 5 = 1113
1113 * 5 + 6 = 5571
4) Answer: C
Series I:
110 + 112 = 231
231 – 102 = 131
131 + 92 = 212
212 – 82 = 148
148 + 72 = 197
Series II:
430 + 112 = 551
551 – 102 = 451
451 + 92 = 532 (Not 532)
532 – 82 = 468
468 + 72 = 517
Directions (5-9) :
5) Answer: D
1 / a + 1 / b + 1 / c = 1 / 10- – – – – – – – 1
1 / b + 1 / c = 3 / a – – – – – – – – – 2
1 / a + 1 / b = 4 / c – – – – – – – – – – 3
From 1 & 2,
1 / a + 3 / a = 1 / 10
4 / a = 1 / 10
1 / a = 1 / 40 ——- 4
From 1 & 3,
4 / c + 1 / c = 1 / 10
5 / c = 1 / 10
1 / c = 1 / 50 —— 5
Substitute 4 & 5 in 1,
1/40 + 1/b + 1/50 = 1/10
1/b = 1/10 – 1/40 – 1/50
1/b = (20 – 5 – 4)/200 = 11/200
“B” has completed the work earlier.
6) Answer: D
A) Gold in final mixture,
g – (36 * 5 / 6) =70, g = 100
Copper in final mixture,
c – (36 * 1 / 6) +12 = 26, c = 20
g:c = 5:1 A is satisfied
B)
g – (42 * 5 / 6) =70, g = 105,
c – (42 * 1 / 6) +6 = 26, c = 27
g:c = 35:9 B is not satisfied
C)
g – (72 * 5 / 6) =70, g = 130,
c – (72 * 1 / 6) +12 = 26, c = 26
g:c = 5:1 C is satisfied
D)
g – (72 * 5 / 6) =70, g = 130,
c – (72 * 1 / 6) +6 = 26, c = 32
g:c = 65:16 D is not satisfied
7) Answer: A
According to the question,
(7x + 8)/(5x + 6) = 43/31
217x + 248 = 215x + 258
2x = 10
= > x = 5
A’s age 7 years ago = (7 * 5 + 8) – 7 = 36
B’s age 5 years after = (5 * 5 + 6) + 5 = 36
8) Answer: A
The share of P, Q and R,
= > [6x * 4 + 6x * (125/100) * 5 + ((6x * (5/4)) – 10000) * 3]: [8x * 9 + (8x + 8000) * 3] : [13x * 12] = 51 : 68 : 104
= > [24x + (75x/2) + (45x/2) – 30000] : [72x + 24x + 24000] : [156x] = 51 : 68 : 104
= > [(168x – 60000) / 2]: [96x + 24000]: [156x] = 51: 68: 104
According to the question,
= > (96x + 24000) / (156x) = (68/104)
= > 96x + 24000 = 102x
= > 6x = 24000
= > x = 4000
The initial investment of Q = 8x = Rs. 32000
9) Answer: B
C.I – S.I = 9600
40000 * [(1 + (4x/100))2 – 1] – (40000 * 2x * 2)/100 = 9600
40000 * [((100 + 4x)/100)2 – 1] – 1600x = 9600
40000 * [(10000 + 800x + 16x2 – 10000)/10000] – 1600x = 9600
4 * (800x + 16x2) – 1600x = 9600
3200x + 64x2 – 1600x = 9600
64x2 + 1600x – 9600 = 0
x2 + 25x – 150 = 0
(x – 5) (x + 30) = 0
x = 5, -30 (Negative value will be eliminated)
The rate of interest per annum for CI = 4x % = 20 %
10) Answer: C
x2 – 23x + 42x – 966 = 0
x(x – 23) +42(x – 23) =0
(x – 23) (x + 42) = 0
x= -42, 23
y2 – 13y – 12y + 156 = 0
y(y – 13) -12(y – 13) =0
(y – 12) (y – 13) = 0
y = 12, 13
Hence, the relationship between x and y cannot be determined
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