Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for SBI Clerk Mains 2020 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
Missing Number Series
Directions (01 – 05): What value should come in the place of (?) in the following number series?
1) I) 12, 30, 75, 187.5, 468.75
II) 2……..78.125. If 78.125 is the nthterm find the value of n
A) 5th term
B) 4th term
C) 6th term
D) 7th term
E) None of these
2) I) 8640, 1440, 288, 72, 24
II) 1560……13. If 13 is the nthterm find the value of n
A) 5th term
B) 4th term
C) 6th term
D) 7th term
E) None of these
3) I) 25, 26, 54, 165, 664, 3325
II) 7…..57. If 57 is the nthterm find the value of n
A) 4th term
B) 6th term
C) 5th term
D) 3rd term
E) None of these
4) I) 14, 52, 140, 290, 445
II) 2…..175. If 175 is the nthterm find the value of n
A) 4th term
B) 6th term
C) 5th term
D) 3rd term
E) 7th term
5) I) 8, 177, 298, 379, 428, 453
II) 11…..301. If 301 is the nthterm find the value of n
A) 4th term
B) 6th term
C) 5th term
D) 3rd term
E) 7th term
Data Interpretation
Directions (06 – 10): Study the following information carefully and answer the questions given below.
The given bar graph shows the speed of the boat in still water (in kmph) in five different days.
6) If the time taken by boat travel 120km on day1 in upstream is 8 hours which is 2 more than the time taken by the same boat on day1 downstream, then what is the distance travelled by boat on day1 in downstream?
A) 120 km
B) 150 km
C) 175 km
D) 125 km
E) None of these
7) If the ratio of the time taken by boat to cover distance in upstream to downstream on day2 is 3:2 and the distance travelled by boat in downstream and upstream is 160 km and 120 km respectively, then what is the speed of the stream on day2?
A) 20 kmph
B) 15 kmph
C) 10 kmph
D) 5 kmph
E) None of these
8) If the distance travelled by boat in downstream on day 3 and day 4 is 200 km and 240 km respectively and the ratio of the time taken by boat to cover the distances in upstream to downstream on day 3 and day 4 is 1: 1 and 1: 1 respectively, then what is the sum of the distance travelled by boat in upstream on day 3 and day 4 together if the time in downstream on day 3 and day 4 is 5 hours and 4 hours respectively?
A) 120 km
B) 110 km
C) 130 km
D) 140 km
E) None of these
9) The distance travelled by boat in upstream on day5 is 80 km. If the speed of the stream on day5 is 5 kmph and the ratio of the time taken by boat in upstream to downstream is 4:3, then what is the difference between the distances travelled by boat in upstream and downstream on day5?
A) 10 km
B) 15 km
C) 20 km
D) 5 km
E) None of these
10) On day2, distance travelled in downstream is 80 km and the time taken in downstream and upstream in the ratio of 2:3. Distance travelled in upstream on day3 is 60 km. If the time taken by downstream on day2 is 2 hours and the distance travelled in downstream on day3 is 30 km more than the distance travelled in upstream on day2. What is the ratio of the distance travelled in upstream in day2 to distance travelled in upstream in day3?
A) 1:2
B) 2:3
C) 3:4
D) 4:5
E) None of these
Answers :
Directions (1-5) :
1) Answer: A
Series I,
12 * 2.5 = 30
30 * 2.5 = 75
75 * 2.5 = 187.5
187.5 * 2.5 = 468.75
Series II,
2 is the 1st term
2 * 2.5 = 5
5 * 2.5 = 12.5
12.5 * 2.5 = 31.25
31.25 * 2.5 = 78.125
78.125 is the 5th term
2) Answer: B
Series I,
8640/6 = 1440
1440 / 5 = 288
288 / 4 = 72
72 / 3 = 24
Series II,
1560 is the 1st term
1560 / 6 = 260
260 / 5 = 52
52 / 4 = 13
13 is the 4th term
3) Answer: A
Series I,
25 * 1 + 1 = 26
26 * 2 + 2 = 54
54 * 3 + 3 = 165
165 * 4 + 4 = 664
664 * 5 + 5 = 3325
Series II,
7 is the 1st term
7 * 1 + 1 = 8
8 * 2 + 2 = 18
18 * 3 + 3 = 57
57 is the 4th term.
4) Answer: C
Series I,
14 * 3 + 10 = 52
52 * 2.5 + 10 = 140
140 * 2 + 10 = 290
290 * 1.5 + 10 = 445
Series II,
2 is the 1st term.
2 * 3 + 10 = 16
16 * 2.5 + 10 = 50
50 * 2 + 10 = 110
110 * 1.5 + 10 = 175
175 is 5th term.
5) Answer: D
Series I,
8 + 132 = 177
177 + 112 = 298
298 + 92 = 379
379 + 72 = 428
428 + 52 = 453
Series II,
11 is 1st term.
11 + 132 = 180
180 + 112 = 301
301 is 3rd term.
Directions (6-10) :
6) Answer: B
Speed of the stream = x
Time taken in upstream = 120/(20 – x) = 8
(20 – x) * 8 = 120
20 – x = 15
x = 5 kmph
Time taken in downstream = 8 – 2 = 6 hours
D/(20 + 5) = 6
D = 150 km
7) Answer: C
(160/(30 + x))/(120/(30 – x)) = 2/3
4 * (30 –x)/[3 * (30 + x)] = 2/3
60 – 2x = 30 + x
3x = 30
x = 10 kmph
8) Answer: C
Speed of the stream on day3 = x
Speed of stream on day4 = y
200/(25 + x) = 5
40 = 25 + x
x = 15 kmph
240/(40 + y) = 4
60 = 40 + y
y = 20 kmph
Distance travelled in upstream on day3 = (25 – 15) * 5 = 50 km
Distance travelled in upstream on day4 = (40 – 20) * 4 = 80 km
Required sum = 50 + 80 = 130 km
9) Answer: A
Time taken by boat in upstream = 80/(25 – 5) = 4 hours
Time taken by boat travelled in downstream = 3 hours
Distance travelled by boat in downstream = 3 * (25 + 5) = 90 km
Required difference = 90 – 80 = 10 km
10) Answer: B
Speed of the stream on day2= x
Time taken in downstream on day2 = 2 hours
80/(30 + x) = 2
60 + 2x = 80
2x = 20
x = 10 kmph
Time taken in upstream on day2 = 3 hours
Distance travelled in upstream on day2 = 3 * (30 – 10) = 60 km
Distance travelled in downstream on day3 = 60 + 30 = 90km
Distance travelled in upstream on day2 = 60 km
Required ratio = 60:90 = 2:3
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This post was last modified on October 27, 2021 9:46 am