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Data Interpretation
Direction (1-6): Study the following information carefully and answer the questions given below.
There are three towns P, Q and R. Certain numbers of offices are established in these towns under scheme A, scheme B and scheme C in 2019.
Scheme A: The number of offices in town P is ¾ of the number of offices in town Q under scheme B. The number of offices in town R is 19/24 of the number of offices in town R under scheme C. The total number of offices in town P and town R is equal under scheme A. The total number of offices under scheme A is 1355.
Scheme B: The total number of office under scheme B is 930. The number of offices in town Q is 170 less than that of number of offices in town P and R together. The number of offices in town P is 2/3 of the number of offices in town P under scheme C.
Scheme C: The number of offices under scheme C is 29/31 of the number of offices under scheme B. The number of office in town R under scheme C is 10 more than under scheme B.
1) In 2020, the number of offices established for town Q under scheme B is increases by 50% and the number of offices established for town R under scheme C is decreased by 75%, then the total number of offices in 2020 for town Q under scheme B and town R under scheme C is equal to the total number of offices in which of the following towns in 2019?
A) Town P under scheme B and town Q under scheme A together
B) Town P under scheme C and town R under scheme C together
C) Town R under scheme B and town P under scheme B together
D) Town Q under scheme A and town R under scheme B together
E) None of those given as options.
2) In town X, the number of offices established under scheme A is 20% more than that of number of offices established for town R under scheme A and the number of offices established under scheme B is 20% less than that of number of offices established for town Q under scheme B and total number of offices in town X is 840, then how many offices are established for town X under scheme C?
A) 150
B) 165
C) 180
D) 194
E) None of these
3) If the revenue of each offices is 10 crore for scheme A and 15 crore for scheme B and 12 crore for scheme C, then how much revenue received from town R under these three schemes (in million)?
A) 124200
B) 134000
C) 217800
D) 154000
E) None of these
4) What is the average number of offices under scheme B and C for town R and town Q together?
A) 310
B) 320
C) 325
D) 345
E) None of these
5) What is the total number of offices under scheme A and B together?
A) 2180
B) 2285
C) 2345
D) 2490
E) None of these
6) What is the ratio of total number of offices under scheme B to scheme C?
A) 29: 31
B) 25: 27
C) 31: 29
D) 27: 25
E) None of these
Data Interpretation
Direction (7-10): Study the following information carefully and answer the questions given below.
7) If the ratio of principal of Vimal to that of Ashraf is 3: 4 and the rate of interest of Ashraf is 20% more than that of Vimal, then what is the interest of Ashraf?
A) Rs.2400
B) Rs.2900
C) Rs.3400
D) Rs.4800
E) None of these
8) At what rate of interest the amount of Nilan becomes five times that of his principal?
A) 100%
B) 150%
C) 200%
D) 250%
E) None of these
9) What is the amount of Ashok, when the principal of Ashok is 30% more than that of Anu?
A) Rs.27583.4
B) Rs.32908.8
C) Rs.34560.5
D) Rs.45080.4
E) None of these
10) What is the principal of Nilan, if the ratio of interest rate of Anu to that of Nilan is 4: 3?
A) Rs.20000
B) Rs.23000
C) Rs.25000
D) Rs.27000
E) None of these
Answers :
Direction (1-5):
Scheme A=>
No. of offices in town P = ¾ * No. of offices in town Q under scheme B — (i)
No. of offices in town R = 19/24 * No. of offices in town R under scheme C — (ii)
Total no. of offices in town P under scheme A = Total no. of offices in town R under scheme A — (iii)
Total number of offices under scheme A = 1355 — (iv)
Scheme B =>
Total number of office under scheme B = 930
No. of offices in town Q = No. of offices in town P and R together – 170
No. of offices in town P and R together = n
=> n + (n – 170) = 930
=> n = 550 = No. of offices in town P and R together
Hence the No. of offices in town Q under scheme B = 550 – 170 = 380
From (i), No. of offices in town P under scheme A = ¾ * 380 = 285
From (iii), Total no. of offices in town R under scheme A = 285
From (ii), No. of offices in town R = 19/24 * No. of offices in town R under scheme C
=> No. of offices in town R under scheme C = 24/19 * 285 = 360
From (iv), No. of offices in town Q under scheme A = 1355 – 285 – 285 = 785
No. of offices in town P under scheme B= 2/3 * No. of offices in town P under scheme C — (v)
Scheme C =>
No. of offices under scheme C = 29/31 * No. of offices under scheme B.
=>No. of offices under scheme C = 29/31 * 930 = 870
No. of office in town R under scheme C = 10 + No. of office in town R under scheme B.
Hence, No. of office in town R under scheme B = 360 – 10 = 350
No. of offices in town P under scheme B = 930 – 380 – 350 = 200
From (v), No. of offices in town P under scheme C = 3/2 * 200 = 300
No. of offices in town Q under scheme C = 870 – 300 – 360 = 210
1) Answer: B
Offices in town Q under scheme B = 150/100 * 380 = 570
Offices in town R under scheme C = 25/100 * 360 = 90
Total number of offices in 2020 for town Q under scheme B and offices for town R under scheme C = 570 + 90 = 660
From the given option, 660 offices obtained only from option B.
2) Answer: D
In Town X, the number of offices established under scheme A = 120/100 * No. of offices in town R under scheme A
= 120/100 * 285 = 342
In Town X, the number of offices established under scheme B = 80/100 * No. of offices in town Q under scheme B
= 80/100 * 380 = 304
In Town X, the number of offices established under scheme C = 840 – 342 – 304 = 194
3) Answer: A
Revenue received from town R under these three schemes = (285 * 10) + (350 * 15) + (360 * 12) = 12420 Crore = 124200 million
4) Answer: C
Average number of offices under scheme B and C for town R and town Q together = (380 + 350 + 210 + 360)/4 = 325
5) Answer: B
Total number of offices under scheme A and B together = 1355 + 930 = 2285
6) Answer: C
Required ratio = 930: 870 = 31: 29
Directions (7-10) :
7) Answer: D
Principal of Ashraf = 4/3 * 30000 = Rs.40000
Rate of interest = 120/100 * 2 = 2.4%
Interest of Ashraf = (40000 * 5 * 2.4)/100 = Rs.4800
8) Answer: C
Amount of Nilan = Rs.26500
Principal = 26500/5 = Rs.5300
n = 2 years
SI = 26500 – 5300 = Rs.21200
r = (SI * 100)/(P * n)
= (21200 * 100)/(5300 * 2) = 200%
9) Answer: A
Principal of Anu = Rs.20000
Principal of Ashok = 130/100 * 20000 = Rs.26000
Amount of Ashok = P * (1 + r/100)n
= 26000 * (1 + 3/100)2
= Rs.27583.4
10) Answer: C
r% = ¾ * 4 = 4%
Let X = Principal
Amount = Principal + SI
=> 26500 = X + (X * 2 * 3)/100
=> X = Rs.25000
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