Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for SBI Clerk Prelims 2020 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
Quadratic equation
Directions (01-05): Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,
1) i) x2-8x+15 = 0
ii) y2-8y+16 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
2) i) x2-30x+225 = 0
ii) y2-10y-75 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
3) i) x2 – 10x + 24 = 0
ii) y2 – 15y + 54 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
4) i) x2Â – 17x + 72 = 0
ii) y2Â – 15y + 56 = 0
A.If x < y
B.If x > y
C.If x ≤ y
D.If x ≥ y
E.If relationship between x and y cannot be determined
5) I) x2Â = x + 182
II) -28y = (y2+ 195)
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
Approximation
Directions (6-10): What approximate value should come in the place of (?) in the following questions?
6) 119.91 % of 9500.02 – 40.02 % of 6399.901 – 59.89 % of 8200.01 =? * 19.912
A.172
B.169
C.196
D.184
E.120
7) 36.01 % of 349.91 + (576.03 ÷ 39.912) * √26.01 =?
A.204
B.218
C.196
D.188
E.176
8) 83.33 % of 299.879 + 10.21 % of 630.02 =?2 – 14.93 % of 319.901
A.19
B.17
C.15
D.13
E.21
9) (1055.94 ÷ √120) * 4.96 +? * √255 = 48.05 * 16.08
A.18
B.22
C.26
D.15
E.12
10) 15.879 * 54.98 – √1370 * 60.919 =? – √2304 * 52.11
A.1104
B.1119
C.1130
D.1145
E.1183
Answers :
1) Answer: C
x2-8x + 15 = 0
x2– 5x – 3x + 15= 0
x (x – 5) – 3 (x – 5) = 0
x = 5,3
y2 – 8y + 16 = 0
y2– 4y – 4y + 16 = 0
y (y – 4) – 4 (y – 4) = 0
y = 4,4
Hence, relationship can’t be determined.
2) Answer: B
x2 – 30x + 225 = 0
x2 -15x – 15x + 225 = 0
x (x – 15) – 15 (x – 15) =0
x = 15,15
y2 – 10y – 75 = 0
y2 – 15y + 5y – 75 = 0
y (y – 15) + 5 (y – 15) = 0
y = 15, -5
Hence, x ≥ y
3) Answer: E
x2 – 10x + 24 = 0
x2 – 6x – 4x + 24 =Â 0
x (x – 6) – 4 (x – 6) = 0
x = 6,4
y2 – 6y – 9y + 54 = 0
y (y – 6) – 9 (y – 6) = 0
y = 6, 9
Hence, x ≤ y
4) Answer: D
From I => x2Â – 17x + 72 = 0
=> x2Â – 8x – 9x + 72 = 0
=> x (x – 8) -9 (x – 8) = 0
=> (x – 8) (x – 9) = 0
=> x = 8, 9
From II => y2Â – 15y + 56 = 0
=>Â y2Â – 8y -7y + 56 = 0
=> y (y – 8) -7 (y – 8) = 0
=> (y – 8) (y – 7) = 0
=> y = 7, 8
Hence, x ≥ y
5) Answer: B
x2Â = x + 182
x2 – x – 182 = 0
x2 – 14x + 13x – 182 = 0
x (x – 14) + 13 (x – 14) = 0
(x + 13) (x – 14) = 0
x = 14, -13
-28y = (y2Â + 195)
y2Â + 28y + 195 = 0
y2Â + 13y + 15y + 195 = 0
y (y + 13) + 15(y + 13) = 0
(y + 15) (y + 13) = 0
y = -15, -13
x ≥ y
6) Answer: C
119.91 % of 9500.02 – 40.02 % of 6399.901 – 59.89 % of 8200.01 =? * 19.912
11400 – 2560 – 4920 =? * 20
? = 196
7) Answer: C
36.01 % of 349.91 + (576.03 ÷ 39.912) * √26.01 =?
126 + 14 * 5 =?
126 + 70 =?
? = 196
8) Answer: A
83.33 % of 299.879 + 10.21 % of 630.02 =?2 – 14.93 % of 319.901
5/6 * 300 + 63 =?2 – 48
250 + 63 + 48 =?2
19 =?
9) Answer: A
(1055.94 ÷ √120) * 4.96 +? * √255 = 48.05 * 16.08
480 +? * 16 = 768
? * 16 = 288
? = 18
10) Answer: B
15.879 * 54.98 – √1370 * 60.919 =? – √2304 * 52.11
16 * 55 – 37 * 61 =? – 48 * 52
880 – 2257 =? – 2496
1119 =?
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