Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for SBI Clerk Prelims 2020 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
Missing number series
Directions (01-05): What value should come in the place of (?) in the following number series?
1) 13, 50, 135, 279, 426.5, ?
A.433.5
B.478.5
C.482.5
D.453.5
E.463.5
2) 8, 152, 273, ?, 454, 518
A.298
B.320
C.343
D.364
E.373
3) 19, 22, 30, 45, 69, ?
A.90
B.98
C.104
D.110
E.114
4) 23, 47, 75, 107, 143, ?
A.219
B.198
C.183
D.176
E.150
5) 19, 40, 84, 153, 249, ?
A.374
B.386
C.398
D.419
E.439
Data Interpretation
Directions (6-10): Study the following information carefully and answer the question given below.
The following table represents the number of students enrolled in six different colleges, percentage of students left the college and percentage of students who passed out the college among those who continued their study in the college.
6) Find the sum of total number of students from all the colleges, who continued their study.
A.7432
B.7223
C.7199
D.7351
E.None of these
7) Number of students passed from college B is approximately what percent of the number of students passed from college D?
A.152
B.180
C.187
D.125
E.None of these
8) Total number of students enrolled in A and B together is what percent more than the number of students enrolled in C and D together?
A.6.134%
B.8.163%
C.9.156%
D.4.146%
178%
9) Find the ratio of number of failed students of college C and college F respectively.
A.1137 : 450
B.960 : 1457
C.341 : 144
D.450 : 137
E.None of these
10) Passed students of college A is approximately what percent of failed students of college C?
A.121 %
B.184 %
C.211 %
D.312 %
E.None of these
Answers :
1) Answer: A
13 * 3 + 11 = 50
50 * 2.5 + 10 = 135
135 * 2 + 9 = 279
279 * 1.5 + 8 = 426.5
426.5 * 1 + 7 =Â 433.5
2) Answer: E
8 + 122Â = 152
152 + 112Â = 273
273 + 102Â =Â 373
373 + 92Â = 454
454 + 82Â = 518
3) Answer: C
19 + (3 * 1) = 22
22 + (4 * 2) = 30
30 + (5 * 3) = 45
45 + (6 * 4) = 69
69 + (7 * 5) =Â 104
4) Answer: C
23 + 24 = 47
47 + 28 = 75
75 + 32 = 107
107 + 36 = 143
143 + 40 =Â 183
5) Answer: A
19 + (21 * 1) = 40
40 + (22 * 2) = 84
84 + (23 * 3) = 153
153 + (24 * 4) = 249
249 + (25 * 5) =Â 374
6) Answer: C
A = (100 – 5)/100 x 1400 = 1330
B = (100 – 8)/100 x 1250 = 1150
C = (100 – 12)/100 x 1550 = 1364
D = (100 – 10)/100 x 900 = 810
E = (100 – 15)/100 x 1300 = 1105
F = (100 – 4)/100 x 1500 = 1440
Required No of students = 1330 + 1150 + 1364 + 810 + 1105 + 1440 = 7199
7) Answer: B
Number of students who continued study in B = (100 – 8)/100 x 1250 = 1150
Passed Students = 76/100 x 1150 = 874
Number of students who continued study in D = (100 – 10)/100 x 900 = 810
Passed Students = 60/100 x 810 = 486
Required percentage = (874/486) x 100 = 179.83% = 180 %
8) Answer: B
Total number of students enrolled in A and B together = 1400 + 1250 = 2650
Total number of students enrolled in C and D together = 1550 + 900 = 2450
Required percentage = (2650 – 2450)/2450 x 100 = 8.163%
9) Answer: C
Number of students who continued study in C = (100 – 12)/100 x 1550 = 1364
Failed = (100-75)/100 x 1364 = 341
Number of students who continued study in F = (100 – 4)/100 x 1500 = 1440
Failed = (100 – 90)/100 x 1440 = 144
Required ratio = 341 : 144
10) Answer: D
Number of students who continued their study from college A = (100 – 5)/100 x 1400 = 1330
Passed = 80/100 x 1330 = 1064
Number of students who continued their study from college C
= (100 – 12)/100 x 1550 = 1364
Failed = (100 – 75)/100 x 1364 = 341
Required percentage = (1064/341) x 100 = 312.023% = 312 %
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