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[WpProQuiz 2602]
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Direction (Q. 1-5): Study the graphs carefully to answer the questions that follow: Total number of flights in 6 different airlines and the percentage of International Flights in them
Directions (Q. 6-10) : What value will come in place of question mark (?) in the given questions ? (You are not expected to calculate the exact value)
6). 18.05 x 8.99 – 52.02 =?
7). 149.96 x 3.02 – 114.57 x 1.93 =?
8). 45.04 ÷ 4.97 = ? ÷ 12.99
9). 135.59 ÷ 7.62 x 2.93 = 75.01% of?
10). 75.05% of (289.96 + 142.01) = ?2
Directions (Q. 21-25): Study the following graph carefully to answer these questions
Number of students (Males & Females) in thousands passed out from various exams in a year.
Directions (Q 26-30): Find the missing number in the following series
26). 21, 35, 30, 44, 39, ?
27). 8, 4.5, 5.5, 13, 56, ?
28). 19, 16, 44, 101, ?
29). 19, 25, 42, 71, 113, ?
30). 42, 51, 67, 97, 148, ?
Directions (31-35): For the two given equations I and II.
Give answer:
a) If p is greater than q.
b) If p is smaller than q.
c) If p is equal to q.
d) If p is either equal to or greater than q.
e) If p is either equal to or smaller than q.
31) I. 6p2+5p+1=0
II. 20q2+9q=-1
32) I. 3p2+2p-1=0
II. 2q2+7q+6=0
33) I. 3p2+15p=-18
II. q2+7q+12=0
34) I. p=√4/√9
II. 9q2-12q+4=0
35) I. p2+13p+42=0
II. q2=36
Answers:
Direction (1-5)
1). Answer a
Total number of flights in SpiceJet = 2000
Number of National Flights in Vistara = 1250 × 60/100 = 750
Number of International Flights in Jet Airways = 3000 × 45/100 = 1350
Total = 750 + 1350 = 2100
Required percentage
= 2000/2100 × 100
= 95%
2). Answer b
Number of National Flights in IndiGo = 2500 × 60/100 = 1500
Number of National Flights in Jet Airways = 3000 × 55/100 = 1650
Number of International Flights in Vistara= 1250 × 40/100 = 500
Number of International Flights in AirAsia= 1000 × 12.5/100 = 125
Required average = 1/4 × (1500 + 1650 + 500 + 125)
= 1/4 × 3775
= 943.75
3). Answer c
Number of International Flights in SpiceJet = 2000 × 27.5/100 = 550
Number of International Flights in GoAir = 2250 × 30/100 = 675
Total = 1225
Number of National Flights in Vistara = 1250 × 60/100 = 750
Number of National Flights in AirAsia = 1000 × 87.5/100 = 875
Total = 1625
Required ratio = 1225: 1625
= 49: 65
4). Answer d
Number of National Flights in Spice Jet = 2000 × 72.5/100
= 1450
Number of National Flights in AirAsia = 1000 × 87.5/100
= 875
Total = (1450 + 875) = 2325
Required percentage = 2325/3000 ×100
= 77.5
5). Answer e
Number of National Flights in IndiGo = 2500 × 60/100
= 1500
Number of National Flights in GoAir = 2250 × 70/100
= 1575
Number of National Flights in Vistara = 1250 × 60/100
= 750
Total = 1500 + 1575 + 750
= 3825
Direction (6-10)
6). Answer d
18.05 x 8.99 – 52.02 =?
18 x9 – 52 =?
162 -52 =?
? = 110
7). Answer b
149.96 x 3.02 – 114.57 x 1.93 = ?
150 x3 -115 x2 = ?
450 – 230 = ?
? = 220
8). Answer d
45.04 ÷ 4.97 = ? ÷ 12.99
45 /5 = ?/13
9 x 13 = ?
? = 117
9). Answer e
135.594 ÷ 7.62 x 2.93 = 75.01% of ?
(136/8) x 3 = (75/100) × ?
17 x3 = (3/4) x ?
? = 68
10). Answer d
75.05% of (289.96 + 142.01) = ?2
75/100 x (290 + 142 ) = ?2
3/4 x432 = ?2
3 x 108 = ?2
324 = ?2
? = √324
? =18
11). Answer: (c)
Consider M & N pipes opened together for x min
M——24min total work
N——-32min 96 units
Efficiency of M is 4
Efficiency of N is 3
7x+4(18-x) = 96
X = 8 minutes
12). Answer: a
2 Bananas 40 Rs
1 banana 20 Rs
(80/100)X = 20
X= 25
Original price for 1 banana = Rs. 25
13). Answer: c
Let x km be the distance
Time1 = x/24 hrs
While travelling at 25% faster speed
24 + 25% 24 = 30 kmph
Time2= x/30 hrs
Total time difference 9 minutes
x/24 – x/30= 9
x = 18km
14). Answer: c
Let total No. of employees be 100
(40 x 390 + 60 x 420)/100 = 408
15). Answer b
Income ratio of Raghu and Raju =5:4
Expense ratio of Raghu and Raju = 2:1
Given,
Raghu’s savings = 5x-2y=12000 — (1)
Raju’s savings = 4x-y=12000 — (2)
Simplify the above equation (1) and (2), we get x= 4000
Raju’s annual income = 16000*12=Rs.192000
16). Answer e
Area of 4 walls of a room
= 2(Length + Breadth) * Height
= 2(12 + 10)* 4 = 176m2
Required cost = 176 x 12.6 = Rs.2217.60
17). Answer a
Total number of ball pens = n(S)
= 6 + 7 = 13
Required probability (6C2 x7C2)/ 13C4= (15x 21)/715 = 63/143
18). Answer a
Total work = 15 x 60 = 900 units
Remaining work = 900 – 12 x 45 = 360 units
Let x men be added to finish the remaining work in 8 days
Then, (12 + x) 8 = 360
Or, 8x = 360 – 96
x= 264/8 =33
19). Answer: b
Let’s assume that the required time = T years
Hence in 2nd case, (6336 – 4800) = (4800’8’T)/100
=> T = (1536’100)/(4800’8)
=> T = 4 years
Let’s suppose that the principal amount be Rs P in 1St case.
Hence, P + (P'((5’4)/100)) = 7200
=> 1.2P = 7200
=> P = Rs 6000
20). Answer b
Let the income of A and B be Rs 9n and 4n respectively and the expenditure of A and B be Rs 7m and 3m respectively.
Hence according to the question; 9n – 7m = 4000… (1)
Similarly; 4n – 3m = 2500… (2)
Solving (1) and (2) we will get; n = 5500, m = 6500
Hence income of A = 9n = Rs 49500, Income of B = 4n = Rs 22000
Direction (21-25)
21). Answer e
Passed students from IBPS Exam= 37500
Passed students from RRB Exam = 17500
Difference = 37500 – 17500
= 20000
22). Answer d
Passed Boys from IBPS Exam and SBI Exam
= 15000 + 17500
Passed Girls from RBI Exam and SSC Exam
= 35000 + 30000
% = 32500/65000 × 100 = 50%
23). Answer b
Passed Girls from RBI Exam = 35000
Passed Girls from All exams = 117500
Approximate % = 35000 / 117500 × 100 = 29.78% = 30%
24). Answer c
Average number of passed students in all Exams
Boys + Girls = Students
IBPS =15000 + 22500= 37500
SBI = 17500 + 20000= 37500
RBI = 27500 + 35000= 62500
SSC = 25000 + 30000= 55000
RRB = 10000 + 7500 = 17500
Total = 210000
Average = 210000/5
= 42000
25). Answer a
Ratio between passed all boys and all girls in all exams
= Boys: Girls
= 92500: 117500
= 37: 47
Direction (26-30)
26). Answer: c
+14, -5, +14, -5 alternatively
27). Answer: d
×0.5+.05, ×1+1, ×2+2, ×4+4, ×8+8
28). Answer: b
Difference of difference
-3…………28………..57………..84
……31………….29………27
29). Answer: e
Difference of difference
6…………17………..29………..42………..56
……11………….12………13………..14
30). Answer: a
The difference of difference is 7, 14, 21, 28…
Direction (31-35)
31). Answer: B)
I. 6p2+5p+1=0
(3p+1)(2p+1)=0
p=-1/3,-1/2
II. 20q2+9q+1=0
(4q+1)(5q+1)=0
q=-1/4,-1/5
∴p<q
32). Answer: A)
I. 3p2+2p-1=0
(3p-1)(p+1)=0
p=1/3,-1
II. 2q2+7q+6=0
(2q+3)(q+2)=0
q=-3/2,-2
p>q
33). Answer: D)
I. 3p2+15p+18=0
(3p+6)(p+3)=0
p=-2,-3
II. q2+7q+12=0
(q+4)(q+3)=0
q=-3,-4
∴p≥q
34). Answer: C)
(3q-2)2=0
q=2/3
∴p=q
35). Answer: E)
I. p2+13p+42=0
(p+7)(p+6)=0
p=-6,-7
II. q2=36
q=±6
∴p≤q
This post was last modified on August 26, 2020 12:42 pm