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[WpProQuiz 2643]
Click “Start Quiz” to attend these Questions and view Solutions
Directions (Q. 1 – 5): What should come in place of the question mark (?) in the following questions?
Directions (Q. 6 – 10): What should be the approximate value come in place of question mark (?).
Directions (Q. 11 – 15): What value should come in place of (?) in the following number series?
Directions (Q. 16 – 20): Study the following information carefully and answer the questions given below:
Directions (Q. 31 – 35): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
a) if x < y
b) if x > y
c) if x ≤ y
d) if x ≥ y
e) if x = y, or relationship between x and y can’t be established.
31. I. 7x + 3y = 8
II. 3x + 2y = 12
II. y = 3√2197
II. y2– 8y + 7 = 0
II. 2y2– 15y + 27 = 0
II. y2 – 2y = 0
Answers:
1). Answer: c)
8(1 / 2) + 4(2 / 7) = 5(1 / 2) + ?
Or, ? = 8(1 / 2) + 4(2 / 7) – 5(1 / 2)
= (8 + 4 – 5) + (1 / 2) + (2 / 7) – (1 / 2)
= 7 + [(7 + 4 – 7) / 14] = 7 + (4 / 14) = 7(2 / 7)
2). Answer: c)
? = 376 – 58.4 × 1.5 × 2.2
= 376 – 192.72 = 183.28
3). Answer: e)
(? × 4680) / 100 = 1183.4 – [(46 × 1250) / 100]
= 1183.4 – 575 = 608.4
? = (608.4 × 100) / 4680 = 13
4). Answer: c)
√? + 9.5 = √2916 – √1681
= 54 – 41 = 13
√? = 13 – 9.5 = 3.5
? = 3.5 × 3.5 = 12.25
5). Answer: e)
? = 4642 + 2368 + 196 – 5986
= 7206 – 5986 = 1220
Direction (6-10)
6). Answer: a)
? = 2 * 36 – 5 = 67 ≈ 70
7). Answer: d)
√? = 1394 / 100 – 7
√? = 14 – 7 = 7
? = 49
8). Answer: a)
3* 12 = ? / 0.8
? = 36*0.8 = 36*(4/5)
? = 28.8 ≈ 30
9). Answer: e)
? = 36 ÷ 9 ÷ 10 + 39
? = 4 / 10 + 39 = 39.4
? = 40
10). Answer: C)
(?)2 = ∛59322 * (428 ÷ 11)
(?)2 = 39 * 39
? = 39
Direction (11-15)
11). Answer: c)
224-16=208
208+32=240
240-48=192
192+64=256
256-80=176.
12). Answer: b)
14=1
24=16
34=81
44 =256
54=625
64=1296.
13). Answer: d)
6*4-1=23
23*4-2=90
90*4-3=357
357*4-4=1424
1424*4-5=5691
14). Answer: b)
5*1.5+1.5=9
9*2.5+2.5=25
25*3.5+3.5=91
91*4.5+4.5=414
414*5.5+5.5=2282.5.
15). Answer: c)
3*4=12
4*12=48
48*576=27648.
Direction (16-20)
16). Answer: b)
Total number of employees working in all the companies in 2010
= 2000 + 1750 + 2200 + 1800 + 1950 + 1500
= 11200
Total number of employees working in all the companies in 2014
= 1060 + 2000 + 1850 + 1650 + 1450 + 1500
= 9510
Required percentage = 11200/9510 x 100 = 120 %
17). Answer: b
Total number of employees working in C and D together in 2011 = 2400 + 1750 = 4150
Total number of employees working in A and B together in 2013 = 1400 + 1650 = 3050
Required percentage = (4150 – 3050)/3050 x 100 = 36.06%
18). Answer: c
Total number of employees working in 2011 = 1600 + 2050 + 2400 + 1750 + 1450 + 1700 = 10950
Total number of employees working in 2012 = 1350 + 1500 + 1200 + 1780 + 1300+ 2050 = 9180
Required ratio = 10950:9180 = 365 : 306
19). Answer: d
Total number of employees working in company B in all the years together
= 1750 + 2050 + 1500 + 1650 + 2000 = 8950
Total number of employees working in company D in all the years together
= 1800 + 1750 + 1780 + 1000 + 1650 = 7980
Required difference = 8950 – 7980 = 970
20). Answer: b
Required sum
= > 1950 + 1450 + 1300 + 1850 + 1450 + 1500 + 1700 + 2050 + 1450 + 1500
= > 16200
21). Answer c
Selling price = 440*70/100 = Rs. 308
Cost price = 308/110*100 = Rs. 280
22). Answer b
By using M1D1H1=M2D2H2
64*50/1/2= 20(50+x)/1/2
By solving
X= 110 men.
23). Answer a
Total Balls = 15
Probability = 6C3 / 15C3 = 4/91
24). Answer d
Distance covered by the first train= 18*40=720m
Distance covered by second train = 720-90=630m
So,
Time taken by the second train to cross the bridge= 630/84*5/18= 27 seconds.
25). Answer d
Total capacity of the tank= 504 units
So, waste pipes empties the tank = 25/504-18/28-21/24=14/504 = 14 litres per minutes
So, waste pipe can empty 60% of the tank = 75/100*36=27 minutes
26). Answer a
Let the distance of one side be x km
x/55 – x/66=1/2
x/330 = 1/2
x = 165 km
27). Answer: b
Volume of the sphere = 4/3πr3 = 4/3 x 22/7 x 14 x 14 x 14
Volume of the cylinder = πr2h = 22/7 x 14 x 14 x 16
Required ratio = [4/3 x 22/7 x 14 x 14 x 14] : [22/7 x 14 x 14 x 16]
= > 7:6
28). Answer: b
According to the question,
44000 x 115/100 x 120/100 x 90/100 = 54648
Required difference = 54648 – 44000 = 10648
29). Answer a
Let the time of downstream and upstream x.
Speed of downstream= 6/x km/hr
Speed of upstream= 4/x km/hr
48/(6/x) + 48/(4/x) = 16
=>20x=16
=> x= 4/5 =0.8
Speed of downstream= 6/x = 6/0.8 = 7.5 km/hr
Speed of upstream= 4/x = 4/0.8 = 5 km/hr
The speed of the stream is,
=> ½ (7.5- 5)
=> 2.5/2 =1.25 km/hr
30). Answer: c
Consider M & N pipes opened together for x min
M——24min total work
N—— 32min 96 units
Efficiency of M is 4
Efficiency of N is 3
7x+4(18-x) = 96
X = 8 minutes
31). Answer: a)
Now, solving both the eqns, we get
eqn (i) x 2 – eqn (ii) x 3
(14x+ 6y=16) – (9x + 6y = 36)
5x = -20
x = -4 and y = 12
Hence, x <y
32). Answer: e)
I. x2= 289
or x = ±17
II. y = 3√2197
y = 13
Hence, we can’t find a relationship between x and y.
33). Answer: c)
I. 8x2 -11x + 3 = 0
8x2 – 8x – 3x +3 = 0
8x(x – 1) – 3(x – 1) = 0
(8x -3)(x – 1) = 0
x =1, 3/8
II. y2– 8y + 7 = 0
y2 – y – 7y + 7 = 0
y (y – 1) – 7(y – 1) = 0
(y – 1) (y – 7) = 0
y = 1, 7
Hence, x ≤ y
34). Answer: c)
I. x2– 2x – 3x + 6 =0
x(x -2) – 3(x -2) = 0
(x -2) (x -3) = 0
x =2, 3
II. 2y2 – 6y – 9y + 27 = 0
2y(y – 3)-9(y -3) = 0
(y- 3) (2y -9) = 0
y = 3, 9/2
Hence, x ≤ y
35). Answer: e)
I. 10x2 -16x + 15x – 24 = 0
2x(5x -8) + 3(5x 8)=0
(2x + 3)(5x +8) = 0
x = -3/2, 8/5
II. y2– 2y = 0
or, y(y -2) = 0
y = 0, 2
ie no relationship exists between x and y.
This post was last modified on August 26, 2020 12:48 pm