Dear Aspirants, Here we have given the Important SSC Exam 2018 Practice Test Papers. Candidates those who are preparing for SSC 2018 can practice these questions to get more confidence to Crack SSC 2018 Examination.
[WpProQuiz 4602]Click here to view Quantitative Aptitude Questions in Hindi
1) A train length 750m crosses a bridge of length 150m in 45 sec. what is the speed of the train in Kmph?
a) 72 Kmph
b) 60 kmph
c) 65 Kmph
d) &5 Kmph
2) If α, β, are the roots of the equations 2x2 – 3x + 2 = 0, form the equation whose roots are roots are α2, β2?
a) 5x2 + x – 4
b) 2x2 – x + 3
c) 5x2 – 4x + 3
d) 4x2 – x + 4
3) The four triangles by joining the pairs of midpoint of the sides of a given triangle are congruent if the given triangle is
a) A right angle triangle
b) An equilateral triangle
c) An isosceles triangle
d) None of these
4) Average of 50 numbers is 100. If the tw0 numbers 50 and 80 are expelled, then find the average of remaining numbers?
a) 99.40
b) 87.04
c) 97.40
d) 50.40
5) Somu lends Rs. 12500 to two different persons for different rate of simple interest per annum. If the difference of simple interest from the person is Rs. 25, then what is the difference between their rates of interest?
a) 0.25
b) 0.5
c) 0.75
d) 0.66
6) If a/x + y/b = 1 and b/y + z/c = 1, then value of x/a +c/z is ?
a) 1
b) 0
c) – 2
d) – 1
7) In ∆ABC, AB = 12 cm, BC = 6 cm, and AC =6 cm. Find the approximate length of the median from vertex A.
a) 10 cm
b) 9 cm
c) 8 cm
d) 7 cm
Direction (8 – 10): Read the instruction carefully and answer the following question.
Given pie chart illustrates the percentage of income of family members per annum. The total income of the family is 2.5 lakhs per month.
8) What is the total annual income of the family, if Ramesh got 10% hike of his monthly salary?
a) 32.2 lakhs
b) 31.2 lakhs c) 35 lakhs
d) 34.1 lakhs
9) What is the difference of highest income and lowest income of the family monthly?
a) 65430
b) 65450
c) 61250
d) 62000
10) What is the ratio of swathi’s monthly income to sakthi’s monthly income?
a) 1: 2
b) 2: 3
c) 3: 4
d) 4: 5
Answers :
1) Answer: b)
Length of the train = 750 m
Length of the bridge = 150 m
Total distance = 750 + 150 = 900
Time = 45 sec
Speed = Distance/ Time = 900 / 45 * 18 / 5 = 60 kmph
2) Answer: d)
As per given data,
α + β = -b/a = -(-3)/2 = 3/2
αβ = 2/2 = 1
For the new equations roots are α2, β2
∴ Sum of the roots α2 + β2 = (α + β)2 – 2 αβ = (3/2)2 – 2(1) = 9/4 – 2 = 1/4
Product of the roots = α2β2 = (αβ) = 12 =1
Required equation = x2 – (Sum of roots) * (products of the roots) = 0
x2 – (1/4)x +1 = 0
4x2 – x + 4 = 0
3) Answer: a)
There is a property of lines joining mid-points of two sides of a triangle.
Property – Line joining the mid-points of two sides is always parallel to the third side.
If you let length of the sides to be AB, BC and AC, then
AD = BD = 1/2AB
BE = CE = 1/2BC
AF = CF = 1/2AC
From the property, we can say that DE is parallel to AC. Similarly, EF is parallel to AB and DF is parallel to BC.
If you draw the figure and see, then you will notice that 3 parallelograms, AFED, FDEC and FDBE.
You can thus equate the parallel sides and we get FD = EB, EF = BD and DE = CF which are halves of the parallel sides.
Now if you check the sides of the four triangles, all of will have the same dimensions. Thus total area of ABC is sum of the areas of the 4 triangles.
4) Answer: c)
Total number (x1 + x2 + x3 + x4+ ……….. x50) = 50
Average of 50 numbers = 100
Sum of Total numbers = 100 * 50 = 5000
If two numbers are expelled 50 + 80 = 130
(5000 – 130)/50 = 4870/ 50 = 97.40
5) Answer: a)
S. I1 – S.I2 = ((PNR1)/ 100) – ((PNR2)/100)
S. I1 – S.I2 = PN/100 (R1 – R2)
250 = 12500 * 2/100 (R1 – R2)
R1 – R2 = 25*100/ 12500*2 = ¼ = 0.25
6) Answer: b)
7) Answer: c)
AB =12 cm
BC = 10cm
AC = 6 cm
Median of vertex A = AD
BD = DC = ½ (BD) = ½ (10) = 5 cm
By Apollonius theorem
AB2 + AC2 = 2 (AD2 + BD2)
122 + 62 = 2 (AD2 + 52)
144 + 36 = 2(AD2 + 52)
90 = AD2 + 25
90 = AD2 + 25
AD2 = 65 ≈ AD = √64 = 8 cm
Direction (8-10) :
8) Answer: b)
Total income monthly = 2.5 lakhs
Total income annually = 2.5* 12 * (40/100) = 1 lakhs
10% hike on monthly salary = 110000
New salary of Ramesh Annually = 110000 * 12 = 13.2 lakhs
Other annual salary = 30 * (60/100) = 18 lakhs
New annual salary of the family = 13. 2 + 18 lakhs = 31.2 lakhs
9) Answer: d)
Highest salary of this family = 2.5 * 12 * 40/100 = 12 lakh
Lowest salary of this family = 2.5 * 12 * 15/ 100= 4.5 lakh
12 – 4.5 = 7.5 lakh / 12 = 62,000
10) Answer: c)
Sakthi’s Monthly income = 2.5 * (20/100) = 50000
Swathi’s monthly income = 2.5 * 15/100 = 37500
Ratio of swathi’s monthly ratio to sakthi’s monthly salary
= 37500 : 50000
= 3 : 4
This post was last modified on December 20, 2018 12:37 pm