Dear Aspirants, Our IBPS Guide team is providing new series of Quants Questions for SBI Clerk/ IBPS Clerk/ ESIC UDC /MTS Prelims so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
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1) A can do a piece of work in 15 days and the ratio of the efficiency of A and B is 4:1. A, B and C together can complete the half of the work in 4 days. If they got the total wages of Rs.5400, then what is the wage of C?
A.Rs.1200
B.Rs.1500
C.Rs.1800
D.Rs.2000
E.None of these
2) A, B and C together can complete the work in 11(1/13) days and C alone complete the same work in 48 days. If the efficiency of A is 50% more than B, in how many days A and C together can complete the work?
A.12 days
B.16 days
C.18 days
D.20 days
E.None of these
3) A alone completes the work in 30 days and the efficiency of A is 300% more than the efficiency of B. If A, B and C together can complete the work in 16 days and they got the total wages of Rs.27000, then what is the wages of C?
A.Rs.9000
B.Rs.12000
C.Rs.10000
D.Rs.6000
E.None of these
4) A alone complete the work in x days and A and B together can complete the work in (x – 4) days. Efficiency of A is double of the efficiency of B. Find the value of x.
A.12
B.15
C.18
D.20
E.None of these
5) A and B together can complete the work in 13 days and A alone complete the work in 39 days. If A and B together can start the work, after 6 days A left the work, in how many days can B complete the remaining work?
A.11 days
B.12 days
C.13 days
D.9 days
E.None of these
6) 4 men and 6 women together can complete the work in 5 days and 6 men and 4 women do the same work in 4 days. In how many days 4 men and 2 women together complete the work?
A.6.25 days
B.4.25 days
C.12.25 days
D.10.25 days
E.8.25 days
7) 30 men can complete a work in 35 days. If x men started the work and worked for 25 days after 25 days, 35 men joined them and finished the remaining work in 10 days, find the value of x.
A.10
B.20
C.30
D.40
E.50
8) A, B and C together can complete three-fourth of the work in 6 days, A and C together can complete two-fifth of the work in 4(4/5) days and B and C together complete 55% of the work in 6 days. In how many days C alone complete the work?
A.20 days
B.15 days
C.24 days
D.18 days
E.12 days
9) A alone completes the work in 16 days and the efficiency of A is 25% less than the efficiency of B. If A, B and C together can complete the work in 6 days, in how many days C alone complete the work?
A.36 days
B.40 days
C.48 days
D.56 days
E.60 days
10) A, B and C together can complete the work in 16 days. If A, B and C started the work together, after 4 days A left from the work and then C and B together can complete the remaining work in 24 days. In how many days A alone complete the work?
A.32 days
B.24 days
C.30 days
D.27 days
E.36 days
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Answers :
1) Answer: C
A = 1/15
Time ratio of A and B = 1:4
B alone complete the work = 4 * 15 = 60 days
C alone complete the work = 1/8 – 1/15 – 1/60
= 15 – 8 – 2/120 = 1/24
Ratio of work done by A, B and C = 1/15:1/60:1/24
= 8:2:5
C’s wages = 5/15 * 5400 = Rs.1800
2) Answer: B
A + B + C together can complete the work = 13/144
C alone complete the work = 1/48
A + B complete the work = 13/144 – 1/48
= 13 – 3/144
= 5/72
Efficiency of A and B = 150:100 = 3:2
Time ratio of A and B = 2:3
1/2x + 1/3x = 5/72
5/6x = 5/72
x = 12
A alone complete the work = 12 * 2 = 24 days
A + C together can complete the work = 1/24 + 1/48
= 1/16
3) Answer: A
A = 1/30
Efficiency of A and B = 400:100 = 4:1
Time ratio of A and B = 1:4
B alone complete the work = 4 * 30 = 120 days
C alone complete the work = 1/16 – 1/30 – 1/120 =(30 – 16 – 4)/480
= 1/48
Ratio of work done by A, B and C = 1/30:1/120:1/48
= 16:4:10
= 8:2:5
C’s wage = 5/15 * 27000 = Rs.9000
4) Answer: A
A + B = x – 4 days
A = x days
Time ratio of A and B = 1:2
B alone complete the work = 2 * x = 2x
1/x + 1/2x = 1/x- 4
3/2x = 1/x – 4
2x = 3x – 12
x = 12
5) Answer: E
A + B = 1/13
A = 1/39
B = 1/13 – 1/39 = 2/39
6/39 + ((6 + x)2)/39 = 1
(12 + 2x)/39 = 11/13
21 = 2x
x = 10.5 days
6) Answer: A
(4m + 6w) * 5 = 4 * (6m + 4w)
20m + 30w = 24m + 16w
4m = 14w
20women complete the work in 5 days
One woman complete the work = 100 days
One man complete the work in 14/(100 * 4) = 200/7 days
Required time = 28/200 + 2/100 = 32/200 = 4/25
Required time = 6.25 days
7) Answer: B
M1D1Â = M2D2
30 x 35 = Â 25x + (x+35) x 10
x = 20
8) Answer: A
A + B + C together can complete the whole work = 4/3 * 6 = 8 days
A + C together can complete the whole work = 5/2 * 24/5 = 12 days
B alone complete the work = 1/8 – 1/12 = 1/24
B + C together can complete the whole work = 100/55 * 6 = 120/11
C alone complete the work = 11/120 – 1/24 = 6/120
Required time = 20 days
9) Answer: C
A alone complete the work = 16 days
Efficiency of A and B = 75:100
Time ratio of A and B = 4:3
B alone complete the work = ¾ * 16 = 12 days
C alone complete the work = 1/6 – 1/12 – 1/16 = (8 – 4 – 3)/48
= 1/48
10) Answer: A
A, B and C together can complete the work in 4 days = 4/16 = ¼
Remaining work = 1 – ¼ = ¾
C and B together can complete the whole work = 4/3 * 24 = 32 days
A alone complete the work = 1/16 – 1/32 = 1/32
Start Quiz
11) A, B and C together can complete a work in 10 days. If C alone complete the work in 20 days and the efficiency of B is double of A, in how many days B alone complete the work?
A.20 days
B.10 days
C.30 days
D.40 days
E.None of these
12) Jeni can do a piece of work in 30 days. Tanu is 20% more efficient than Jeni. How many days will Tanu take to do the same piece of work?
A.15 days
B.20 days
C.25 days
D.30 days
E.None of these
13) 20 men and 13 women can complete a work in 5 days. 15 men and 20 women can complete the same work in 6 days. In how many days 6 men and 8 women can complete the work?
A.20 days
B.30 days
C.40 days
D.15 days
E.8 days
14) A, B and C together can complete the work in 16 days and C alone complete the work in 20 days. If A, B and C started the work together and after 10 days A and B left the work, in how many days C alone complete the remaining work?
A.6 days
B.5.5 days
C.6.5 days
D.8 days
E.7.5 days
15) P and Q together can complete a work in 6 2/3 days while P alone can complete the work in 12 days, then in how many days the work will get complete, if they work on alternative days starting with P?
A.15 ½ days
B.12 days
C.13 ¼ days
D.16 days
E.None of these
16) Basker and Sekar together can do a work together in 9 days. Basker is 1 2/3 times as efficient as Sekar. Then how long will Basker alone take do complete the work?
A.12 days
B.14 2/5 days
C.16 days
D.18 2/5 days
E.None of these
17) A can complete 80% of a work in 16 days and B can complete 75% of the work in 18 days. If A and B both start working together, in how many days the work will be completed?
A.10(10/11) days
B.12(10/11) days
C.8(10/11) days
D.11(10/11) days
E.None of these
18) 6 men and 15 women complete a work in 30 days. If each man takes thrice the time taken by woman, in how many days 17 men finish the same work?
A.60 days
B.80 days
C.75 days
D.90 days
E.99 days
19) A and B together can do a work in 16 days, B and C together can do it in 24 days while C and A together can do it in 32 days. Then in how many days C alone will complete the work?
A.176 days
B.184 days
C.192 days
D.180 days
E.None of these
20) A and B together can complete a work in 13(5/7) days and B alone complete the half of the work in 16 days. If A started the work and after 6 days, he left the work, then in how many days B alone complete the remaining work?
A.12 days
B.18 days
C.24 days
D.30 days
E.None of these
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Answers :
11) Answer: C
A + B + C = 1/10
C = 1/20
A + B = 1/10 – 1/20 = 1/20
1/2x + 1/x = 1/20
(1 + 2)/2x = 1/20
1/x = 1/30
12) Answer: C
Ratio of time taken by Jeni and Tanu = 120: 100 = 6: 5
Let Tanu takes x days to do the work.
=> 6: 5::30: x
=> x = 5 * 30/6 = 25 days
13) Answer: D
5 * (20 m + 13 w) = 6 * (15 m + 20 w)
100 m + 65 w = 90 m + 120 w
10 m = 55 w
2 m = 11 w
20 m + 13 w = 110 w + 13 w = 123 w
6 m + 8 w = 33 w + 8 w = 41 w
Women              days
123Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5
41Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ?
Then
Required number of days = (123 * 5) / 41 = 15 days
14) Answer: E
A + B + C = 1/16
C = 1/20
A + B = 1/16 – 1/20 = (5 – 4)/80 = 1/80
10/80 + (x + 10)/20 = 1
10 + 4x + 40 = 80
4x = 30
x = 7(1/2) = 7.5 Days
15) Answer: C
P and Q together can complete a work in = 6 2/3 days = 20/3 days
(P + Q)’s one day work = 3/20
P alone can complete the work in = 12 days
P’s one day work = 1/12
Q’s one day work = 3/20 – 1/12 = (36 – 20) / (20 * 12) = 1/15
Q can complete the work in 15 days
Total units = 60 (LCM of 12, 15)
A’s one day work = 5 units
B’s one day work = 4 units
Work done in 2 days = 5 + 4 = 9 units
Work done in 12 days = 9 * 6 = 54 units
Work will be completed in = 12 + 1 + ¼ = 13 ¼ days
16) Answer: B
(Basker’s 1 day’s work): (Sekar’s 1 day’s work) = 5/3: 1 = 5: 3
Let Basker’s and Sekar’s 1 day’s work be 5x and 3x.
Then, 5x + 3x = 1/9
=> x = 1/72
Hence, Basker’s 1 day’s work = 1/72 * 5 = 5/72
=>He will take 14 2/5 days to complete the whole work.
17) Answer: A
A = 100/80 * 16 = 20 days
B = 100/75 * 18 = 24 days
A + B = 1/20 + 1/24
= 44/20 * 24
Required time = 120/11 = 10(10/11) days
18) Answer: D
w = 3m
Total work = (6m + 15w) = 1/30
6m + 45m = 1/30
51m = 1/30
51m * 30 = 17m * ?
? = 90 days
19) Answer: C
(A + B)’s one day work = (1/16)
(B + C)’s one day work = (1/24)
(C + A)’s one day work = (1/32)
2*(A + B + C)’s one day work = (1/16) + (1/24) + (1/32) = 13/96
(A + B + C)’s one day work = 13/(96 * 2) = 13/192
C’s one day work = (A + B + C) – (A + B)
= > (13/192) – (1/16)
= > (13 – 12)/192
= > 1/192
‘C’ can complete a whole work in = 192 days
20) Answer: C
A + B = 96/7
B = 2/1 * 16 = 32 days
A = 7/96 – 1/32 = 1/24
6/24 + x/32 = 1
x/32 = 1 – 1/4
x/32 = 3/4
x = 24 days
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