Dear Aspirants, Our IBPS Guide team is providing new series of Quants Questions for IBPS PO Prelims so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
1) A train crosses a 360 m long stationary train in 24 seconds and the same train crosses a man standing in a platform in 9.6 seconds. Find the speed of the train?
A.60 kmph
B.80 kmph
C.45 kmph
D.90 kmph
E.72 kmph
2) A train crosses a 280 m long tunnel in 23.2 seconds and the same train crosses a pole in 12 seconds. Find the length of the train?
A.250 m
B.300 m
C.350 m
D.400 m
E.450 m
3) Train A crosses train B running in the opposite direction at the speed of 45 kmph in 21 seconds and the ratio of the length of train A to B is 16:19. If the difference between length of train A and B is 60 m, then find the speed of train A?
A.60 km/hr
B.55 km/hr
C.80 km/hr
D.75 km/hr
E.90 km/hr
4) A train can cross an electric pole in 10 seconds and a bridge of 440 m long in 32 seconds. Find the time taken by (in seconds) the train to cross a car running at 27 km/hr in the same direction as that of train?
A.16 seconds
B.18 seconds
C.24 seconds
D.28 seconds
E.None of these
5) Two trains cross each other in 14 seconds and 182 seconds when running in the opposite direction and the same direction respectively. Find the speed of the faster train is how much % more than that of slower train?
A.25%
B.20%
C.15%
D.16.66%
E.14.28%
6) Ratio of the speed of train A to B is 4:5 and the length of train A is 400 m. If train B crosses a pole in 28.8 seconds and train A crosses train B running in the same direction in 4.4 minutes, then find the length of train B?
A.420 m
B.450 m
C.480 m
D.510 m
E.540 m
7) A train crosses a man standing on a platform in 24 seconds and the same train crosses a 520 m tunnel in 50 seconds. Find the speed of the train?
A.60 kmph
B.45 kmph
C.72 kmph
D.80 kmph
E.90 kmph
8) A train is running at a speed of 24kmph and passes a tunnel of length 100m in 36 seconds. Find the ratio between the length of the train and the length of the tunnel.
A.5: 7
B.7: 5
C.3: 2
D.2: 3
E.None of these
9) Train A crosses a pole in 12 seconds and also crosses train B running in the opposite direction at the speed of 40 kmph in 36 seconds. If the ratio of the length of train A to B is 1:3, then find the speed of train A?
A.90 kmph
B.80 kmph
C.60 kmph
D.100 kmph
E.None of these
10) Train A crosses train B running in the same direction at the speed of 54 kmph in 75 seconds. If the length of train A is 450 meters and the speed of train A is 108 kmph, then find the length of train B?
A.600 m
B.625 m
C.650 m
D.675 m
E.700 m
Answers :
1) Answer: D
Length of train = x m
Speed of train = y km/hr
x + 360 = y * 5/18 * 24
3x + 1080 = 20y
x = y * 5/18 * 9.6
18x = 48y
3x = 8y
8y + 1080 = 20y
y = 90 km/hr
2) Answer: B
Length of train = x m
Speed of train = y km/hr
x + 280 = y * 5/18 * 23.2
9x + 2520 = 58y
x = y * 5/18 * 12
3x = 10y
9x + 2520 = 58 * (3x/10)
90x + 25200 = 174x
x = 300 m
3) Answer: D
19x – 16x = 60
x = 20
Length of train A = 20 * 16 = 320 m
Length of train B = 19 * 20 = 380 m
Speed of train A = y km/hr
320 + 380 = (45 + y) * 5/18 * 21
y = 75 km/hr
4) Answer: A
Let L be the length of train and S be the speed in m/s
L = S x 10
Also
L + 440 = S x 32
10S + 440 = 32S
22S = 440
S = 20 m/s
Length of train = 10 x 20 = 200 m
Speed of car = 27 x 5/18 = 7.5 m/s
Time taken by train to cross a car running in same direction as that of train = 200 / (20 – 7.5)
= 16 seconds
Hence answer is option A
5) Answer: D
Let the speed of two trains be X m/s and Y m/s
When two trains crosses each other is opposite direction
Sum of lengths = (X + Y) x 14
When two trains crosses each other in same direction
Sum of lengths = (X – Y) x 182
So, (X + Y) x 14 = (X – Y) x 182
X + Y = 13X – 13Y
X/Y = 7/6
Required % = 1*100/6= 16.66%
6) Answer: C
Speed of train A = 4x
Speed of train B = 5x
Length of train B = 5x * 5/18 * 28.8
= 40x
400 + 40x = (5x – 4x) * 5/18 * (4.4 * 60)
400 + 40x = 220x /3
x = 12
Length of train B = 40 * 12 = 480 m
7) Answer: C
Length of train = x m
Speed of train = y km/hr
x = y * 5/18 * 24
x = 20y/3
x + 520 = y * 5/18 * 50
x + 520 = 125y/9
20y/3 + 520 = 125y/9
y = 72 kmph
8) Answer: B
Speed = Distance/time
24 * 5/18 = (x + 100)/36
=> x = 240 – 100 = 140m = Length of train
Required ratio = 140: 100 = 7: 5
9) Answer: E
Speed of train A = y km/hr
Length of train A = x m
Length of train B = 3x
x = y * 5/18 * 12
3x = 10y
3x + x = (y + 40) * 5/18 * 36
4x = 10y + 400
x = 400
y = 400 * 3/10 = 120
10) Answer: D
Length of train B + 450 = (108 – 54) * 5/18 * 75
Length of train B= 1125 – 450
= 675 m
11) Train A crosses 200 m long train B running in opposite direction in 18 seconds. If train B crosses 100m long platform in 27 seconds and train A crosses a man running same direction in 18 seconds, then find the length of train A?
A.60 kmph
B.80 kmph
C.40 kmph
D.Cannot be determined
E.None of these
12) A train of length 150 m crosses a platform in 30 seconds and it crosses a man standing on the platform in 20 seconds. Find the length of the platform.
A.55 m
B.75 m
C.80 m
D.85 m
E.None of these
13) Ratio of the speed of train A to B is 3:5 and both are moving in opposite direction. Length of the train A to B is in the ratio of 2:3. Both trains cross each other in 20 seconds. Length of train A is 160 meter. Find the speed of both the trains in kmph.
A.20 kmph, 40 kmph
B.27 kmph, 35 kmph
C.35 kmph, 45 kmph
D.27 kmph, 45 kmph
E.None of these
14) The length of train B is 25% more than the length of train A and the speed of train A is double the speed of train B. Train A crosses a man running in opposite direction at the speed of 10 kmph in 14.4 seconds and train A crosses train B running in opposite direction in 25.2 seconds, then find the length of train B.
A.300 m
B.250 m
C.400 m
D.450 m
E.350 m
15) Length of train A is x m and length of train B is (x – 80) m. If train A crosses train B running opposite direction at the speed of 30 kmph in 19.2 seconds and train A crosses a platform in 24 seconds. If the speed of train A is 60 kmph, then what is the time taken by train B crosses the same platform?
A.28.4 seconds
B.30.4 seconds
C.38.4 seconds
D.36.4 seconds
E.42.4 seconds
16) Train A crosses train B running opposite direction in 12 seconds. Train A crosses a man standing in a platform in 8 seconds and the length of train A is 200 m. If train B crosses a pole in 18 seconds, then find the speed of train B?
A.40 kmph
B.50 kmph
C.60 kmph
D.80 kmph
E.70 kmph
17) A train crosses 320m long tunnel in 25.2 seconds and also crosses a man standing in a platform in 10.8 seconds. What is the time taken by the train crosses a car running in the same direction at the speed of 20 kmph?
A.10.8 seconds
B.12.8 seconds
C.14.4 seconds
D.18 seconds
E.None of these
18) Train A crosses train B running in same direction in 60 seconds and train B crosses a pole in 8 seconds. If the ratio of the length of train A to B is 3:2 and train B is faster than A, then find the speed of train A?
A.40 kmph
B.60 kmph
C.90 kmph
D.Cannot be determined
E.None of these
19) The length of the train and that of the platform are equal. If the speed of train is 90km/hr, then the train crosses the platform in 60 seconds, then what is the length of the train (in meters)?
A.750m
B.625m
C.800m
D.700m
E.675m
20) A train crosses an electric pole in 18 seconds and also crosses a 450 m long tunnel in 45 seconds. Find the length of the train?
A.300 m
B.360 m
C.200 m
D.240 m
E.450 m
Answers :
11) Answer: D
Length of train A = x m
Speed of train A = y Kmph
Speed of train B = z Kmph
x + 200 = (y + z) * 5/18 * 18
x + 200 = 5y + 5z
200 + 100 = z * (5/18) * 27
600 = 15z
z = 40 kmph
Speed of man is not given.
12) Answer: B
When train crosses the man,
Speed of the train = 150/20 = 7.5 m/sec
Length of the train + length of the platform = 7.5 x 30 = 225
Length of the platform = 225 – 150 = 75 m
13) Answer: D
Ratio of length = 2:3
Total length of both the train = 5
Length train A = 160
2’s = 160
5’s = 400 meter
Ratio of speed = 3:5
Speed of train A = 3x
Speed of train B = 5x
Relative speed = 8x
Time = distance/speed
20 = 400/8x
x = 5/2 m/sec = 5/2 x 18/5 = 9 km/hr
Speed of train A = 3 x 9 = 27 km/hr
Speed of train B = 5 x 9 = 45 km/hr
14) Answer: E
Length of train A = 4x
Length of train B = 4x *125/100 = 5x
Speed of train B = y
Speed of train A = 2y
4x = (2y + 10) * 5/18 * 14.4
x – 2y = 10
9x = 3y * 5/18 * 25.2
9x = 21y
3x = 7y
(7y/3) – 2y = 10
y = 30
x = 70
Length of train B = 5 * 70 = 350 m
15) Answer: C
x + x – 80 = 90 * 5/18 * 19.2
2x – 80 = 480
x = 280 m
Length of platform = y
280 + y = 60 * 5/18 * 24
y = 120 m
Required time = (200 + 120)/(30 * 5/18) = 38.4 seconds
16) Answer: C
Length of train B = x m
Speed of train A = a Kmph
Speed of train B = b Kmph
200 = a * 5/18 * 8
a = 90 kmph
200 + x = (b + 90) * 5/18 * 12
600 + 3x = (b + 90) * 10
x = b * 5/18 * 18
x = 5b
600 + 3 * (5b) = 10b + 900
5b = 300
b = 60 kmph
17) Answer: C
Length of train = x m
Speed of train = y Kmph
x = y * 5/18 * 10.8
x = 3y
x + 320 = y * 5/18 * 25.2
3y + 320 = 7y
y = 80 kmph
x = 3 * 80 = 240 m
Required time = 240 /((80 – 20) * 5/18) = 14.4 seconds
18) Answer: D
Length of train A = 3x m
Length of train B = 2x m
Speed of train A = a Kmph
Speed of train B = b Kmph
3x + 2x = (b – a) * 5/18 * 60
3x = 10b – 10a
2x = b * 5/18 * 8
9x = 10b
We cannot find the answer.
19) Answer: A
Let the length of the train = x m
Length of the train = Length of the platform
90 X 5/18 = 25m/sec
According to the question,
2x/25 = 60
2x = 25 x 60
X = 750m
20) Answer: A
Length of train = x m
Speed of train = y kmph
x = y * 5/18 * 18
x = 5y
x + 450 = y * 5/18 * 45
5y + 450 = 12.5y
y = 60
x = 60 * 5 = 300 m
21) Train A crosses train B of the same length moving in the opposite direction in 20 seconds. If train A crosses a standing man in 18 seconds with the speed of 72 kmph, then find the speed of train B?
A.24 m/sec
B.18 m/sec
C.16 m/sec
D.12 m/sec
E.None of these
22) Train A crosses a platform of length 280 m in 38 seconds with the speed of 72 kmph. If the length of train A is 80 m more than the length of train B and train B crosses a 100 m long tunnel in 30 seconds, then find the difference between the speed of train A and B?
A.18 kmph
B.12 kmph
C.15 kmph
D.8 kmph
E.None of these
23) A train crosses 360 m long platform in 32 seconds and the train also crosses a dog standing in a platform in 17.6 seconds. Find the speed of the train?
A.60 kmph
B.80 kmph
C.100 kmph
D.90 kmph
E.72 kmph
24) Train A crosses a pole in 18 seconds and also crosses train B is running in the same direction in 2 minutes. If the speed of train B is 25% more than that of A and the length of train B is 240 m, then find the length of train A?
A.260 m
B.360 m
C.450 m
D.440 m
E.560 m
25) A train crosses a tower in 20.25 seconds and also crosses a 150 m long bridge in 27 seconds. Find the speed of the train?
A.60 kmph
B.72 kmph
C.80 kmph
D.90 kmph
E.None of these
26) A train crosses a 420 m long platform in 36 seconds at the speed of 90 kmph. If the speed of the train is decreased by 16.67%, then find the time taken by train to cross a 240 m long bridge?
A.9.6 seconds
B.12 seconds
C.10 seconds
D.16.5 seconds
E.None of these
27) A train crosses a car is running in the opposite direction at the speed of 24 kmph in 18 seconds. If the speed of train is double that of car, then find the time taken by the train to cross 140 m long platform?
A.37.5 seconds
B.25 seconds
C.30 seconds
D.28.8 seconds
E.14.4 seconds
28) Train A crosses train B is running in the same direction in 108 seconds and also train A crosses a tower in 21.6 seconds. If the speed of train B is 33(1/3)% more than the speed of train A, then find the time taken by train B crosses a pole?
A.14.4 seconds
B.12 seconds
C.18 seconds
D.10.8 seconds
E.Cannot be determined
29) Ratio of the speed of trains A and B is 4:5. Train A is 160 m long and train B is 240 m long and train B travels at the speed of 50 kmph. If the two trains A and B are running in opposite direction, then find the time taken by both trains to cross each other?
A.16 seconds
B.21 seconds
C.12 seconds
D.27 seconds
E.None of these
30) Train A crosses a standing man in 24 seconds and also crosses train B running in the opposite direction at the speed of 54 kmph in 21.6 seconds. If the ratio of the length of trains A and B is 4:5 respectively, then find the speed of train A?
A.27 kmph
B.54 kmph
C.45 kmph
D.36 kmph
E.None of these
Answers :
21) Answer: C
Speed of the train A=72*5/18=20 m/sec
Length of the train A=20*18=360 m
Length of the train B=360 m
(20+x)=(360+360)/20
(20+x)=36
x=16 m/sec
22) Answer: B
Length of train A + 280 = 72 * 5/18 * 38
Length of train A = 480 m
Length of train B = 480 – 80 = 400 m
400 + 100 = Speed of train B * 5/18 * 30
Speed of train B = 60 kmph
Required difference = 72 – 60 = 12 kmph
23) Answer: D
Length of train = x
Speed of train = y
x + 360 = y * 5/18 * 32
9x + 3240 = 80y
x = y * 5/18 * 17.6
9x = 44y
44y + 3240 = 80y
y = 90 kmph
24) Answer: B
Speed of train A = 4x
Speed of train B = 4x * 125/100 = 5x
Length of train A = y
y = 4x * 5/18 * 18
y = 20x
20x + 240 = (5x – 4x) * 5/18 * 120
60x + 240 * 3 = 100x
x = 18
Length of train A = 18 * 20 = 360 m
25) Answer: C
Length of train = x
Speed of train = y
x = y * 5/18 * 20.25
x = 5.625y
x + 150 = y * 5/18 * 27
2x + 300 = 15y
5.625y * 2 + 300 = 15y
y = 80 kmph
26) Answer: A
Length of the train=x
(x+420)=90*5/18*36
x=480 m
Speed of the train is decreased by 16.67%=90*5/6=75 m/s
Required time=(480+240)/75=720/75=9.6 seconds
27) Answer: A
Length of train = (24 + 24 * 2) * 5/18 * 18
= 360 m
Required time = (360 + 140)/(24 * 2) * 5/18
= 37.5 seconds
28) Answer: D
Speed of train A = 3x
Speed of train B = 400/300 * 3x = 4x
Length of train A = y
Length of train B = z
y = 3x * 5/18 * 21.6
y = 18x
y + z = (4x – 3x) * 5/18 * 108
y + z = 30x
z = 30x – 18x = 12x
Required time = 12x/4x * 5/18 = 10.8 seconds
29) Answer: A
Speed of train A=50*4/5=40 kmph
Relative speed=40+50=90 kmph
Time taken by both trains A and B to cross each other=x
160+240=90*5/18*x
400*18/5*1/90=x
x=16 seconds
30) Answer: D
Length of train A=4x
Length of train B=5x
Let speed of train A =y
4x=y*5/18*24
3x=5y
4x+5x=(y+54)*5/18*21.6
3x=(2y+54*2)
3x=2y+108
y=36 kmph
This post was last modified on August 3, 2023 1:37 pm