Dear Readers, Here we have given the Useful Tricks for Alpha Numeric Series for IBPS Exams 2017. Candidates those who are preparing for the upcoming IBPS Exams 2017 can make use of it.
No need of writing the series in reverse order
Step 1:Â Count the total number of alpha-numericals =32
Step 2:Â As we are considering half of the series, divide by two =32/2=16
Required 21R = 16R+5R
Instead of taking 5R take 5L (since first half is reversed)
16R+5L=f (Answer)
2) Which element will be twenty-first from the right end, if second half of the series is reversed?Â
Step 1:Â Count the total number of alpha-numericals =32
Step 2:Â As we are considering half of the series, divide by two =32/2=16
Required 21R = 16R+5R
16R+5R (belongs to first half do not reverse) =4 (Answer)Â
=To From
=5R – 16R
=11R
=11L (trick: To reverse order change R to L)
=Â¥ (Answer)Â
=To From
=7L + 16R
=23R=2 (Answer)
1) Which letter will be 4th to the right of 11th letter from your left hand of English Alphabets?
=To from
=4R + 11L
=15L =O (Multiples of 5) (Use this trick to find 15L)
E
|
J
|
O
|
T
|
Y
|
5
|
10
|
15
|
20
|
25
|
=To From
=6L – 20L
=14L=N (Multiples of 5) (Use this trick to find 14L)
E
|
J
|
O
|
T
|
Y
|
5
|
10
|
15
|
20
|
25
|
=5L + 12R
=17R= (Find from reverse alphabetical order) (How we find if it is from right side)
=J (Answer)
E
|
J
|
O
|
T
|
Y
|
5
|
10
|
15
|
20
|
25
|
Step 2:
A
|
1
|
26
|
B
|
2
|
25
|
C
|
3
|
24
|
D
|
4
|
23
|
E
|
5
|
22
|
F
|
6
|
21
|
G
|
7
|
20
|
H
|
8
|
19
|
I
|
9
|
18
|
J
|
10
|
17
|
K
|
11
|
16
|
L
|
12
|
15
|
M
|
13
|
14
|
N
|
14
|
13
|
O
|
15
|
12
|
P
|
16
|
11
|
Q
|
17
|
10
|
R
|
18
|
9
|
S
|
19
|
8
|
T
|
20
|
7
|
U
|
21
|
6
|
V
|
22
|
5
|
W
|
23
|
4
|
X
|
24
|
3
|
Y
|
25
|
2
|
Z
|
26
|
1
|
4) Which letter will be 3rd to the right of 15th from the right?
=3R – 15R
=12R=O (Since from Reverse alphabetical order)